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Zachary is saving money and plans on making monthly contributions into an account earning an annual interest rate of 
4.2% compounded monthly. If Zachary would like to end up with 
$8,000 after 21 months, how much does he need to contribute to the account every month, to the nearest dollar? Use the following formula to determine your answer.

A=d(((1+i)^(n)-1)/(i))

A= the future value of the account after 
n periods

d= the amount invested at the end of each period

i= the interest rate per period

n= the number of periods
Answer:

Zachary is saving money and plans on making monthly contributions into an account earning an annual interest rate of 4.2% 4.2 \% compounded monthly. If Zachary would like to end up with $8,000 \$ 8,000 after 2121 months, how much does he need to contribute to the account every month, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:

Full solution

Q. Zachary is saving money and plans on making monthly contributions into an account earning an annual interest rate of 4.2% 4.2 \% compounded monthly. If Zachary would like to end up with $8,000 \$ 8,000 after 2121 months, how much does he need to contribute to the account every month, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:
  1. Identify Given Values: Identify the given values from the problem.\newlineA (future value of the account) = $8,000\$8,000\newlinen (number of periods) = 2121 months\newlinei (interest rate per period) = 4.2%4.2\% annual interest rate compounded monthly\newlineFirst, we need to convert the annual interest rate to a monthly interest rate by dividing by 1212 (since there are 1212 months in a year).\newlinei = 4.2%12\frac{4.2\%}{12}\newlinei = 0.04212\frac{0.042}{12}\newlinei = 0.00350.0035
  2. Convert Annual Rate: Substitute the values into the formula.\newlineWe have the formula A=d×((1+i)n1)/iA = d \times \left(\left(1 + i\right)^{n} - 1\right) / i.\newlineNow we substitute the values we have into the formula.\newlineA=$8,000A = \$8,000\newlinei=0.0035i = 0.0035\newlinen=21n = 21\newlineWe need to find dd.
  3. Substitute Values: Solve for dd using the formula.\newline$8,000=d×((1+0.0035)211)/0.0035\$8,000 = d \times \left(\left(1 + 0.0035\right)^{21} - 1\right) / 0.0035\newlineNow we calculate the right side of the equation step by step.\newlineFirst, calculate (1+i)n(1 + i)^n:\newline(1+0.0035)21(1 + 0.0035)^{21}
  4. Solve for dd: Calculate the compound factor.(1+0.0035)211.0759(1 + 0.0035)^{21} \approx 1.0759Now we subtract 11 from the compound factor.1.075910.07591.0759 - 1 \approx 0.0759
  5. Calculate Compound Factor: Divide by the interest rate per period.\newline0.0759/0.003521.68570.0759 / 0.0035 \approx 21.6857\newlineNow we have the denominator of the formula.
  6. Divide by Interest Rate: Solve for the monthly contribution dd.
    $8,000=d×21.6857\$8,000 = d \times 21.6857
    Now we divide both sides by 21.685721.6857 to solve for dd.
    d$8,000/21.6857d \approx \$8,000 / 21.6857
    d368.85d \approx 368.85
  7. Solve for Monthly Contribution: Round the monthly contribution to the nearest dollar.\newlineZachary needs to contribute approximately $369\$369 every month.

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