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Yuki works at an aquarium. To clean a tank, she calculates 7900\frac{7}{900} of the tank's total volume, and she adds that much cleaning solution to the tank. For a certain tank, this works out to be 213L2 \frac{1}{3}L of cleaning solution. What is the total volume of the tank?\newline_____liters\_\_\_\_\_ \text{liters}

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Q. Yuki works at an aquarium. To clean a tank, she calculates 7900\frac{7}{900} of the tank's total volume, and she adds that much cleaning solution to the tank. For a certain tank, this works out to be 213L2 \frac{1}{3}L of cleaning solution. What is the total volume of the tank?\newline_____liters\_\_\_\_\_ \text{liters}
  1. Convert to Improper Fraction: Convert the mixed number to an improper fraction. \newline2132 \frac{1}{3} liters can be converted to an improper fraction by multiplying the whole number by the denominator of the fraction and adding the numerator, then placing the result over the original denominator.\newline213=(2×3+1)/3=(6+1)/3=732 \frac{1}{3} = (2 \times 3 + 1)/3 = (6 + 1)/3 = \frac{7}{3} liters.
  2. Set up Equation: Set up the equation to find the total volume of the tank.\newlineWe know that 7900\frac{7}{900} of the tank's volume is equal to 73\frac{7}{3} liters. Let's call the total volume of the tank VV. So, we can write the equation as:\newline7900×V=73\frac{7}{900} \times V = \frac{7}{3}
  3. Solve for V: Solve for V, the total volume of the tank.\newlineTo solve for VV, we need to isolate VV on one side of the equation. We can do this by multiplying both sides of the equation by the reciprocal of 7900\frac{7}{900}.\newlineV=(73)(9007)V = \left(\frac{7}{3}\right) * \left(\frac{900}{7}\right)
  4. Simplify Equation: Simplify the equation.\newlineWe can cancel out the 77 in the numerator of the first fraction and the 77 in the denominator of the second fraction.\newlineV=(13)(9001)V = \left(\frac{1}{3}\right) * \left(\frac{900}{1}\right)\newlineV=9003V = \frac{900}{3}
  5. Calculate Total Volume: Calculate the total volume of the tank.\newline9003=300\frac{900}{3} = 300.\newlineV=300V = 300 liters

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