You're at a clothing store that dyes your clothes while you wait. You get to pick from 4 pieces of clothing (shirt, pants, socks, or hat) and 3 colors (purple, blue, or orange). If you randomly pick the piece of clothing and the color, what is the probability that you'll end up with socks that aren't blue?

Calculate Total Outcomes: Count total possible outcomes for picking any piece of clothing in any color. Total outcomes = Number of clothing pieces * Number of colors = 4 * 3 = 12Count Favorable Outcomes: Count the favorable outcomes for picking socks that aren't blue. Favorable outcomes = Number of colors (not blue) * 1 (for socks) = 2 * 1 = 2Calculate Probability: Calculate the probability of the favorable outcome. P(non-blue socks) = Favorable outcomes / Total outcomes = 2 / 12 = 1 / 6

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You're at a clothing store that dyes your clothes while you wait. You get to pick from $4$ pieces of clothing (shirt, pants, socks, or hat) and $3$ colors (purple, blue, or orange). $\newline$ If you randomly pick the piece of clothing and the color, what is the probability that you'll end up with socks that aren't blue?

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Q. You're at a clothing store that dyes your clothes while you wait. You get to pick from

4

pieces of clothing (shirt, pants, socks, or hat) and

3

colors (purple, blue, or orange).

\newline

If you randomly pick the piece of clothing and the color, what is the probability that you'll end up with socks that aren't blue?

Calculate Total Outcomes: Count total possible outcomes for picking any piece of clothing in any color. $\newline$ Total outcomes = Number of clothing pieces $\times$ Number of colors $\newline$ $= 4 \times 3$ $\newline$ $= 12$
Count Favorable Outcomes: Count the favorable outcomes for picking socks that aren't blue. $\newline$ Favorable outcomes = Number of colors (not blue) $\times 1$ (for socks) $\newline$ $= 2 \times 1$ $\newline$ $= 2$
Calculate Probability: Calculate the probability of the favorable outcome. $\newline$ $P(\text{non-blue socks}) = \frac{\text{Favorable outcomes}}{\text{Total outcomes}}$ $\newline$ $= \frac{2}{12}$ $\newline$ $= \frac{1}{6}$