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You need to rent a moving truck for a day. You have identified two companies that rent trucks. Company A charges $50 per day plus $0.25 per mile. Company B charges $35 per day plus $0.30 per mile For how many miles will the cost of renting be the same?
_____ miles

You need to rent a moving truck for a day. You have identified two companies that rent trucks. Company A charges $50 \$ 50 per day plus $0.25 \$ 0.25 per mile. Company B B charges $35 \$ 35 per day plus $0.30 \$ 0.30 per mile For how many miles will the cost of renting be the same?\newline_____\_\_\_\_\_miles

Full solution

Q. You need to rent a moving truck for a day. You have identified two companies that rent trucks. Company A charges $50 \$ 50 per day plus $0.25 \$ 0.25 per mile. Company B B charges $35 \$ 35 per day plus $0.30 \$ 0.30 per mile For how many miles will the cost of renting be the same?\newline_____\_\_\_\_\_miles
  1. Set up equation: Let's denote the number of miles driven as ' extit{m}'. We need to set up an equation where the cost of renting from Company A is equal to the cost of renting from Company B.\newlineCompany A's cost: $50+$0.25m\$50 + \$0.25m\newlineCompany B's cost: $35+$0.30m\$35 + \$0.30m\newlineSet the costs equal to each other to find the number of miles where they are the same.\newline$50+$0.25m=$35+$0.30m\$50 + \$0.25m = \$35 + \$0.30m
  2. Subtract to isolate terms: Subtract $35\$35 from both sides to isolate the terms with 'm' on one side.\newline$50$35+$0.25m=$0.30m\$50 - \$35 + \$0.25m = \$0.30m\newline$15+$0.25m=$0.30m\$15 + \$0.25m = \$0.30m
  3. Subtract to isolate 'm' terms: Now subtract $0.25m\$0.25m from both sides to get the 'm' terms on one side and constants on the other.\newline$15=$0.30m$0.25m\$15 = \$0.30m - \$0.25m\newline$15=$0.05m\$15 = \$0.05m
  4. Divide to solve for 'm: Divide both sides by $0.05\$0.05 to solve for 'm'.$15/$0.05=m\$15 / \$0.05 = mm=300m = 300

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