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You need to rent a moving truck for a day. You have identified two companies that rent trucks. Company A charges $50\$50 per day plus $0.25\$0.25 per mile. Company B charges $35\$35 per day plus $0.30\$0.30 per mile. For how many miles will the cost of renting be the same? miles\text{ miles}

Full solution

Q. You need to rent a moving truck for a day. You have identified two companies that rent trucks. Company A charges $50\$50 per day plus $0.25\$0.25 per mile. Company B charges $35\$35 per day plus $0.30\$0.30 per mile. For how many miles will the cost of renting be the same? miles\text{ miles}
  1. Set up equation: Let's denote the number of miles driven as ' extit{m}'. We need to set up an equation where the cost of renting from Company A is equal to the cost of renting from Company B.\newlineCompany A's cost: $50+$0.25m\$50 + \$0.25m\newlineCompany B's cost: $35+$0.30m\$35 + \$0.30m\newlineSet the two costs equal to each other to find the number of miles where they will be the same.\newline$50+$0.25m=$35+$0.30m\$50 + \$0.25m = \$35 + \$0.30m
  2. Subtract to isolate terms: Subtract $35\$35 from both sides to isolate the terms with 'm' on one side.\newline$50$35+$0.25m=$35$35+$0.30m\$50 - \$35 + \$0.25m = \$35 - \$35 + \$0.30m\newline$15+$0.25m=$0.30m\$15 + \$0.25m = \$0.30m
  3. Subtract to get 'm' terms: Now subtract $0.25m\$0.25m from both sides to get the 'm' terms on one side and the constants on the other.$15+$0.25m$0.25m=$0.30m$0.25m\$15 + \$0.25m - \$0.25m = \$0.30m - \$0.25m$15=$0.05m\$15 = \$0.05m
  4. Divide to solve for 'm: Divide both sides by $0.05\$0.05 to solve for 'm'.\newline$15/$0.05=$0.05m/$0.05\$15 / \$0.05 = \$0.05m / \$0.05\newlinem=300m = 300

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