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Yesterday, between noon and midnight, the temperature dropped by 
30^(@)F. If the temperature was 
-6.5^(@)F at midnight, what was it at noon?
Answer: 
^(@)F

Yesterday, between noon and midnight, the temperature dropped by 30F 30^{\circ} \mathrm{F} . If the temperature was 6.5F -6.5^{\circ} \mathrm{F} at midnight, what was it at noon?\newlineAnswer: \square F { }^{\circ} \mathrm{F}

Full solution

Q. Yesterday, between noon and midnight, the temperature dropped by 30F 30^{\circ} \mathrm{F} . If the temperature was 6.5F -6.5^{\circ} \mathrm{F} at midnight, what was it at noon?\newlineAnswer: \square F { }^{\circ} \mathrm{F}
  1. Understand the Problem: Understand the problem.\newlineWe need to find the temperature at noon given that the temperature dropped by 30°F30\degree F from noon to midnight and was 6.5°F-6.5\degree F at midnight.
  2. Set Up Equation: Set up the equation.\newlineLet the temperature at noon be represented by TT. The temperature dropped by 30F30\,^\circ\text{F} to reach 6.5F-6.5\,^\circ\text{F} at midnight. So, the equation is:\newlineT30F=6.5FT - 30\,^\circ\text{F} = -6.5\,^\circ\text{F}
  3. Solve for T: Solve for T.\newlineAdd 30°F30\degree F to both sides of the equation to find the temperature at noon (TT).\newlineT30°F+30°F=6.5°F+30°FT - 30\degree F + 30\degree F = -6.5\degree F + 30\degree F\newlineT=23.5°FT = 23.5\degree F
  4. Check the Result: Check the result.\newlineIf the temperature at noon was 23.5°F23.5\degree\text{F} and it dropped by 30°F30\degree\text{F}, then at midnight it would be:\newline23.5°F30°F=6.5°F23.5\degree\text{F} - 30\degree\text{F} = -6.5\degree\text{F}\newlineThis matches the given information, so there is no math error.

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