Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

y=(x-2)(x+8)
The given equation represents a parabola in the 
xy-plane. Which of the following equivalent forms of the equation displays the 
y intercept of the parabola as a constant or coefficient?
Choose 1 answer:
(A) 
y=x^(2)+6x-16
(B) 
y=(x+3)^(2)-25
(c) 
y+24=(x+2)(x+4)
(D) 
y+25=(x+3)^(2)

y=(x2)(x+8) y=(x-2)(x+8) \newlineThe given equation represents a parabola in the xy x y -plane. Which of the following equivalent forms of the equation displays the y y intercept of the parabola as a constant or coefficient?\newlineChoose 11 answer:\newline(A) y=x2+6x16 y=x^{2}+6 x-16 \newline(B) y=(x+3)225 y=(x+3)^{2}-25 \newline(C) y+24=(x+2)(x+4) y+24=(x+2)(x+4) \newline(D) y+25=(x+3)2 y+25=(x+3)^{2}

Full solution

Q. y=(x2)(x+8) y=(x-2)(x+8) \newlineThe given equation represents a parabola in the xy x y -plane. Which of the following equivalent forms of the equation displays the y y intercept of the parabola as a constant or coefficient?\newlineChoose 11 answer:\newline(A) y=x2+6x16 y=x^{2}+6 x-16 \newline(B) y=(x+3)225 y=(x+3)^{2}-25 \newline(C) y+24=(x+2)(x+4) y+24=(x+2)(x+4) \newline(D) y+25=(x+3)2 y+25=(x+3)^{2}
  1. Expand quadratic equation: Expand the given quadratic equation to find the y-intercept.\newlineThe y-intercept occurs when x=0x = 0. To find the y-intercept in the equation, we need to have the equation in standard form, which is y=ax2+bx+cy = ax^2 + bx + c, where cc is the y-intercept.\newliney=(x2)(x+8)y = (x - 2)(x + 8)\newliney=x2+8x2x16y = x^2 + 8x - 2x - 16\newliney=x2+6x16y = x^2 + 6x - 16
  2. Compare with answer choices: Compare the expanded form with the answer choices.\newlineWe have found that the expanded form of the given equation is y=x2+6x16y = x^2 + 6x - 16. Now we need to compare this with the answer choices to see which one matches and shows the y-intercept as a constant or coefficient.\newline(A) y=x2+6x16y = x^2 + 6x - 16\newline(B) y=(x+3)225y = (x + 3)^2 - 25\newline(C) y+24=(x+2)(x+4)y + 24 = (x + 2)(x + 4)\newline(D) y+25=(x+3)2y + 25 = (x + 3)^2
  3. Identify correct answer: Identify the correct answer choice.\newlineThe correct answer choice will be the one that matches the expanded form we found in Step 11 and clearly shows the yy-intercept as a constant or coefficient. From the answer choices, we can see that choice (A) matches our expanded form and displays the yy-intercept 16-16 as a constant.

More problems from Domain and range of quadratic functions: equations