Xavier measured a line to be 15.2 inches long. If the actual length of the line is 14.9 inches, then what was the percent error of the measurement, to the nearest tenth of a percent?Answer:________ %
Q. Xavier measured a line to be 15.2 inches long. If the actual length of the line is 14.9 inches, then what was the percent error of the measurement, to the nearest tenth of a percent?Answer:________ %
Understand formula for percent error: Understand the formula for percent error.The formula for percent error is: Percent Error = (∣Measured Value−Actual Value∣/Actual Value)×100%Here, the measured value is 15.2 inches, and the actual value is 14.9 inches.
Plug values into formula: Plug the values into the percent error formula.Percent Error = (∣15.2−14.9∣/14.9)×100%
Calculate absolute difference: Calculate the absolute difference between the measured value and the actual value.Absolute difference = ∣15.2−14.9∣=0.3 inches
Divide difference by actual value: Divide the absolute difference by the actual value.Division result=14.90.3
Perform division for decimal form: Perform the division to find the decimal form of the percent error.Division result=0.020134228
Convert decimal to percentage: Convert the decimal to a percentage.Percent Error = 0.020134228×100%=2.0134228%
Round percent error: Round the percent error to the nearest tenth of a percent.Rounded Percent Error = 2.0%