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x^(2)+x+2=0

x2+x+2=0 x^{2}+x+2=0

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Q. x2+x+2=0 x^{2}+x+2=0
  1. Identify Equation Type: Identify the type of equation.\newlineThe given equation x2+x+2=0x^2 + x + 2 = 0 is a quadratic equation in the standard form ax2+bx+c=0ax^2 + bx + c = 0, where a=1a = 1, b=1b = 1, and c=2c = 2.
  2. Apply Quadratic Formula: Apply the quadratic formula to find the solutions.\newlineThe quadratic formula is x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}. For our equation, a=1a = 1, b=1b = 1, and c=2c = 2.
  3. Calculate Discriminant: Calculate the discriminant.\newlineThe discriminant is the part of the quadratic formula under the square root: b24acb^2 - 4ac. Let's calculate it: (1)24(1)(2)=18=7(1)^2 - 4(1)(2) = 1 - 8 = -7.
  4. Determine Root Nature: Determine the nature of the roots.\newlineSince the discriminant is negative 7 -7 , the equation has two complex solutions.
  5. Calculate Solutions: Calculate the solutions using the quadratic formula. x=1±721=1±i72x = \frac{-1 \pm \sqrt{-7}}{2\cdot1} = \frac{-1 \pm i\sqrt{7}}{2}, where ii is the imaginary unit.
  6. Write Final Solutions: Write the final solutions.\newlineThe solutions to the equation x2+x+2=0x^2 + x + 2 = 0 are x=(1+i7)/2x = (-1 + i\sqrt{7}) / 2 and x=(1i7)/2x = (-1 - i\sqrt{7}) / 2.

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