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x^(2)+5x+3=0

x2+5x+3=0 x^{2}+5 x+3=0

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Q. x2+5x+3=0 x^{2}+5 x+3=0
  1. Identify the quadratic equation: Identify the quadratic equation to be solved.\newlineThe given quadratic equation is x2+5x+3=0x^{2} + 5x + 3 = 0. We need to find the values of xx that satisfy this equation.
  2. Use the quadratic formula: Use the quadratic formula to find the solutions.\newlineThe quadratic formula is x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}, where aa, bb, and cc are the coefficients of the quadratic equation ax2+bx+c=0ax^2 + bx + c = 0. For our equation, a=1a = 1, b=5b = 5, and c=3c = 3.
  3. Calculate the discriminant: Calculate the discriminant (b24ac)(b^2 - 4ac).\newlineThe discriminant is the part of the quadratic formula under the square root, which is b24acb^2 - 4ac. For our equation, it is (5)24(1)(3)=2512=13(5)^2 - 4(1)(3) = 25 - 12 = 13.
  4. Apply the discriminant: Apply the discriminant to the quadratic formula.\newlineNow that we have the discriminant, we can find the solutions using the quadratic formula: x=5±132×1x = \frac{-5 \pm \sqrt{13}}{2 \times 1}.
  5. Simplify the solutions: Simplify the solutions.\newlineThe solutions are x=5+132x = \frac{-5 + \sqrt{13}}{2} and x=5132x = \frac{-5 - \sqrt{13}}{2}.
  6. Check the solutions: Check the solutions for any mathematical errors.\newlineBy substituting the solutions back into the original equation, we can verify that they satisfy the equation. This step is to ensure there are no math errors.

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