Find the solutions of the quadratic equation. x^(2)+2x-50=-2

Move and Set Equal: First, we need to move all terms to one side of the equation to set it equal to zero. x^2 + 2x - 50 + 2 = 0 x^2 + 2x - 48 = 0Factor the Equation: Now, we need to factor the quadratic equation. We are looking for two numbers that multiply to -48 and add up to 2. The numbers 8 and -6 satisfy these conditions because 8 * -6 = -48 and 8 + (-6) = 2. So, we can factor the equation as: (x + 8)(x - 6) = 0Apply Zero Product Property: Next, we apply the zero product property, which states that if a product of two factors is zero, then at least one of the factors must be zero. Therefore, we set each factor equal to zero and solve for x: x + 8 = 0 or x - 6 = 0Solve for x: Solve the first equation for x: x + 8 = 0 x = -8Solve for x: Solve the second equation for x: x - 6 = 0 x = 6

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Q. Find the solutions of the quadratic equation.

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x^{2}+2x-50=-2

Move and Set Equal: First, we need to move all terms to one side of the equation to set it equal to zero. $\newline$ $x^2 + 2x - 50 + 2 = 0$ $\newline$ $x^2 + 2x - 48 = 0$
Factor the Equation: Now, we need to factor the quadratic equation. $\newline$ We are looking for two numbers that multiply to $-48$ and add up to $2$ . $\newline$ The numbers $8$ and $-6$ satisfy these conditions because $8 \times -6 = -48$ and $8 + (-6) = 2$ . $\newline$ So, we can factor the equation as: $\newline$ $(x + 8)(x - 6) = 0$
Apply Zero Product Property: Next, we apply the zero product property, which states that if a product of two factors is zero, then at least one of the factors must be zero. $\newline$ Therefore, we set each factor equal to zero and solve for $x$ : $\newline$ $x + 8 = 0$ or $x - 6 = 0$
Solve for x: Solve the first equation for x: $\newline$ $x + 8 = 0$ $\newline$ $x = -8$
Solve for x: Solve the second equation for x: $\newline$ $x - 6 = 0$ $\newline$ $x = 6$