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Wyatt is the oldest of three siblings whose ages are consecutive integers. If the sum of their ages is , find Wyatt's age.Answer:
Full solution
Q. Wyatt is the oldest of three siblings whose ages are consecutive integers. If the sum of their ages is , find Wyatt's age.Answer:
- Denote Wyatt's Age: Let's denote Wyatt's age as . Since the siblings have consecutive ages, the other two siblings would be and years old. The sum of their ages is given as . We can write this as an equation:
- Simplify Equation: Now, let's simplify the equation by combining like terms:
- Isolate Term with W: Next, we add to both sides of the equation to isolate the term with :
- Solve for W: Now, we divide both sides of the equation by to solve for W:
- Check Solution: Wyatt's age, , is . To check if this is correct, we can add the ages of all three siblings:Wyatt's age: Second sibling's age: Third sibling's age: Sum of ages: The sum matches the given total age of , so our solution is correct.
