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Write an explicit formula for 
a_(n), the 
n^("th ") term of the sequence 
24,-12,6,dots
Answer: 
a_(n)=

Write an explicit formula for an a_{n} , the nth  n^{\text {th }} term of the sequence 24,12,6, 24,-12,6, \ldots \newlineAnswer: an= a_{n}=

Full solution

Q. Write an explicit formula for an a_{n} , the nth  n^{\text {th }} term of the sequence 24,12,6, 24,-12,6, \ldots \newlineAnswer: an= a_{n}=
  1. Identify Sequence Type: Identify whether the given sequence is geometric or arithmetic. The sequence 24,12,6,24, -12, 6, \ldots has a common ratio between consecutive terms, as each term is obtained by multiplying the previous term by a constant. To find this constant, we can divide the second term by the first term: 12/24=1/2-12 / 24 = -1/2. Similarly, dividing the third term by the second term gives 6/12=1/26 / -12 = -1/2. Since the ratio is consistent, the sequence is geometric.
  2. Use Explicit Formula: Use the explicit formula for a geometric sequence, an=a1×r(n1)a_n = a_1 \times r^{(n-1)}, where a1a_1 is the first term and rr is the common ratio. For the sequence 24,12,6,24, -12, 6, \ldots, the first term, a1a_1, is 2424 and the common ratio, rr, is 12-\frac{1}{2}.
  3. Substitute Values: Substitute the values of a1a_1 and rr into the formula to write an expression to describe the sequence. The expression for the sequence 24,12,6,extellipsis24, -12, 6, extellipsis is a_n = 24 imes (- rac{1}{2})^{(n-1)}.

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