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Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.\newlineGabrielle is selling her handmade jewelry online. Yesterday, she sold 44 bracelets and 1010 necklaces, for a profit of $212\$212. Today, she made a profit of $260\$260 by selling 1010 bracelets and 1010 necklaces. How much profit does Gabrielle earn from each piece?\newlineGabrielle earns a profit of $\$\underline{\hspace{1cm}} from every bracelet and $\$\underline{\hspace{1cm}} from every necklace.

Full solution

Q. Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.\newlineGabrielle is selling her handmade jewelry online. Yesterday, she sold 44 bracelets and 1010 necklaces, for a profit of $212\$212. Today, she made a profit of $260\$260 by selling 1010 bracelets and 1010 necklaces. How much profit does Gabrielle earn from each piece?\newlineGabrielle earns a profit of $\$\underline{\hspace{1cm}} from every bracelet and $\$\underline{\hspace{1cm}} from every necklace.
  1. Define Profit Equations: Let's denote the profit Gabrielle earns from each bracelet as b b and from each necklace as n n . The first equation comes from the sales of yesterday: 44 bracelets and 1010 necklaces made a profit of $\(212\).\(\newline\)Which equation represents the provided information?\(\newline\)\(4\)b + \(10\)n = \(212\)
  2. Sales from Yesterday: The second equation comes from today's sales: \(10\) bracelets and \(10\) necklaces made a profit of \(\$260\). Which equation represents the provided information? \(10b + 10n = 260\)
  3. Sales from Today: System of equations:\(\newline\)\(4b + 10n = 212\)\(\newline\)\(10b + 10n = 260\)\(\newline\)We can solve this system using the method of substitution or elimination. Let's use elimination to solve for one of the variables.
  4. System of Equations: To eliminate \( n \), we can multiply the first equation by \(-1\) to make the coefficients of \( n \) opposites.\(\newline\)\(-1\) * (\(4\)b + \(10\)n) = \(-1\) * \(212\)\(\newline\)\(-4\)b - \(10\)n = \(-212\)\(\newline\)Now we have:\(\newline\)\(-4\)b - \(10\)n = \(-212\)\(\newline\)\(10\)b + \(10\)n = \(260\)
  5. Eliminate Variable n: Add the two equations together to eliminate \( n \).\(\newline\)(\(-4\)b - \(10\)n) + (\(10\)b + \(10\)n) = \(-212\) + \(260\)\(\newline\)\(-4\)b - \(10\)n + \(10\)b + \(10\)n = \(48\)\(\newline\)\(6\)b = \(48\)\(\newline\)Now, solve for \( b \).\(\newline\)b = \(48\) / \(6\)\(\newline\)b = \(8\)
  6. Add Equations: Now that we have the value for \( b \), we can substitute it back into one of the original equations to solve for \( n \). Let's use the first equation:\(\newline\)\(4\)b + \(10\)n = \(212\)\(\newline\)\(4\)(\(8\)) + \(10\)n = \(212\)\(\newline\)\(32\) + \(10\)n = \(212\)\(\newline\)\(10\)n = \(212\) - \(32\)\(\newline\)\(10\)n = \(180\)\(\newline\)n = \(180\) / \(10\)\(\newline\)n = \(18\)

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