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Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.\newlineThe owner of two hotels is ordering towels. He bought 1414 hand towels and 4141 bath towels for his hotel in Kensington, spending a total of $521\$521. He also ordered 5050 hand towels and 4545 bath towels for his hotel in Yardley, spending $745\$745. How much does each towel cost?\newlineA hand towel costs $\$_____, and a bath towel costs $\$_____.

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Q. Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.\newlineThe owner of two hotels is ordering towels. He bought 1414 hand towels and 4141 bath towels for his hotel in Kensington, spending a total of $521\$521. He also ordered 5050 hand towels and 4545 bath towels for his hotel in Yardley, spending $745\$745. How much does each towel cost?\newlineA hand towel costs $\$_____, and a bath towel costs $\$_____.
  1. Define Costs: Let's denote the cost of a hand towel as xx dollars and the cost of a bath towel as yy dollars.\newlineThe first equation represents the total cost of hand towels and bath towels for the Kensington hotel:\newline14x+41y=52114x + 41y = 521
  2. Equations for Hotels: The second equation represents the total cost of hand towels and bath towels for the Yardley hotel: 50x+45y=74550x + 45y = 745
  3. Elimination Method: We now have a system of two equations with two variables:\newline14x+41y=52114x + 41y = 521\newline50x+45y=74550x + 45y = 745\newlineWe can solve this system using either substitution or elimination. Let's use the elimination method to eliminate one of the variables.
  4. Multiply and Align Coefficients: Multiply the first equation by 5050 and the second equation by 1414 to align the coefficients of xx: \newline(14x+41y)×50=521×50(14x + 41y) \times 50 = 521 \times 50\newline(50x+45y)×14=745×14(50x + 45y) \times 14 = 745 \times 14\newlineThis gives us:\newline700x+2050y=26050700x + 2050y = 26050\newline700x+630y=10430700x + 630y = 10430
  5. Subtract to Eliminate x: Subtract the second new equation from the first new equation to eliminate x:\newline(700x+2050y)(700x+630y)=2605010430(700x + 2050y) - (700x + 630y) = 26050 - 10430\newline700x+2050y700x630y=2605010430700x + 2050y - 700x - 630y = 26050 - 10430\newline1420y=156201420y = 15620
  6. Solve for y: Solve for y by dividing both sides of the equation by 14201420: \newliney=156201420y = \frac{15620}{1420}\newliney=11y = 11
  7. Substitute Back for xx: Now that we have the value of yy, we can substitute it back into one of the original equations to find xx. Let's use the first original equation:\newline14x+41(11)=52114x + 41(11) = 521\newline14x+451=52114x + 451 = 521
  8. Solve for x: Subtract 451451 from both sides of the equation to solve for xx: \newline14x=52145114x = 521 - 451\newline14x=7014x = 70
  9. Final Cost Calculation: Divide both sides of the equation by 1414 to find the value of xx:x=7014x = \frac{70}{14}x=5x = 5
  10. Final Cost Calculation: Divide both sides of the equation by 1414 to find the value of xx: \newlinex=7014x = \frac{70}{14}\newlinex=5x = 5We have found the cost of each hand towel and each bath towel:\newlineA hand towel costs $5\$5, and a bath towel costs $11\$11.

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