Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.Two brothers went shopping at a back-to-school sale where all shirts were the same price, and all the shorts too. The younger brother spent $181 on 10 new shirts and 7 pairs of shorts. The older brother purchased 7 new shirts and 7 pairs of shorts and paid a total of $154. How much did each item cost?Each shirt cost $_____, and each pair of shorts cost $_____.
Q. Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.Two brothers went shopping at a back-to-school sale where all shirts were the same price, and all the shorts too. The younger brother spent $181 on 10 new shirts and 7 pairs of shorts. The older brother purchased 7 new shirts and 7 pairs of shorts and paid a total of $154. How much did each item cost?Each shirt cost $_____, and each pair of shorts cost $_____.
Define Prices: Let's denote the price of one shirt as s and the price of one pair of shorts as p. The younger brother's purchase can be represented by the equation:10s + 7p = 181
Younger Brother's Purchase: Similarly, the older brother's purchase can be represented by the equation: 7s+7p=154
Older Brother's Purchase: We now have a system of equations:10s+7p=1817s+7p=154We can use either substitution or elimination to solve this system. Let's use elimination to solve for one of the variables.
System of Equations: To eliminate p, we can subtract the second equation from the first:(10s + 7p) - (7s + 7p) = 181 - 15410s - 7s + 7p - 7p = 181 - 1543s = 27
Elimination Method: Now we can solve for s:3s = 27s = 27 / 3s = 9So, each shirt costs \(9\).
Solve for s: With the price of each shirt known, we can substitute \( s = 9 \) into one of the original equations to find \( p \). Let's use the second equation:\(\newline\)\(7\)s + \(7\)p = \(154\)\(\newline\)\(7\)(\(9\)) + \(7\)p = \(154\)\(\newline\)\(63\) + \(7\)p = \(154\)
Substitute for p: Now we solve for \( p \):\(\newline\)\(7\)p = \(154\) - \(63\)\(\newline\)\(7\)p = \(91\)\(\newline\)p = \(91\) / \(7\)\(\newline\)p = \(13\)\(\newline\)So, each pair of shorts costs 13.
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