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Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.\newlineTwo brothers went shopping at a back-to-school sale where all shirts were the same price, and all the shorts too. The younger brother spent $181\$181 on 1010 new shirts and 77 pairs of shorts. The older brother purchased 77 new shirts and 77 pairs of shorts and paid a total of $154\$154. How much did each item cost?\newlineEach shirt cost $\$_____, and each pair of shorts cost $\$_____.

Full solution

Q. Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.\newlineTwo brothers went shopping at a back-to-school sale where all shirts were the same price, and all the shorts too. The younger brother spent $181\$181 on 1010 new shirts and 77 pairs of shorts. The older brother purchased 77 new shirts and 77 pairs of shorts and paid a total of $154\$154. How much did each item cost?\newlineEach shirt cost $\$_____, and each pair of shorts cost $\$_____.
  1. Define Prices: Let's denote the price of one shirt as s s and the price of one pair of shorts as p p . The younger brother's purchase can be represented by the equation:\newline1010s + 77p = 181181
  2. Younger Brother's Purchase: Similarly, the older brother's purchase can be represented by the equation: 7s+7p=1547s + 7p = 154
  3. Older Brother's Purchase: We now have a system of equations:\newline10s+7p=18110s + 7p = 181\newline7s+7p=1547s + 7p = 154\newlineWe can use either substitution or elimination to solve this system. Let's use elimination to solve for one of the variables.
  4. System of Equations: To eliminate p p , we can subtract the second equation from the first:\newline(1010s + 77p) - (77s + 77p) = 181181 - 154154\newline1010s - 77s + 77p - 77p = 181181 - 154154\newline33s = 2727
  5. Elimination Method: Now we can solve for s s :\newline33s = 2727\newlines = 2727 / 33\newlines = 99\newlineSo, each shirt costs \(9\).
  6. Solve for s: With the price of each shirt known, we can substitute \( s = 9 \) into one of the original equations to find \( p \). Let's use the second equation:\(\newline\)\(7\)s + \(7\)p = \(154\)\(\newline\)\(7\)(\(9\)) + \(7\)p = \(154\)\(\newline\)\(63\) + \(7\)p = \(154\)
  7. Substitute for p: Now we solve for \( p \):\(\newline\)\(7\)p = \(154\) - \(63\)\(\newline\)\(7\)p = \(91\)\(\newline\)p = \(91\) / \(7\)\(\newline\)p = \(13\)\(\newline\)So, each pair of shorts costs 1313.

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