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Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.\newlineA clothing store is donating socks to various charities. The store gave 66 regular packs and 44 value packs to a homeless shelter, which contained a total of 312312 pairs of socks. For foster children, the store donated 66 regular packs and 66 value packs, which equaled 354354 pairs. How many pairs of socks are in each pack?\newlineThere are _\_ pairs of socks in each regular pack and _\_ pairs in each value pack.

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Q. Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.\newlineA clothing store is donating socks to various charities. The store gave 66 regular packs and 44 value packs to a homeless shelter, which contained a total of 312312 pairs of socks. For foster children, the store donated 66 regular packs and 66 value packs, which equaled 354354 pairs. How many pairs of socks are in each pack?\newlineThere are _\_ pairs of socks in each regular pack and _\_ pairs in each value pack.
  1. Set up equations: Set up the system of equations based on the given information.\newlineThe store gave 66 regular packs and 44 value packs to a homeless shelter, which contained a total of 312312 pairs of socks. This can be represented by the equation:\newline6r+4v=3126r + 4v = 312\newlineFor foster children, the store donated 66 regular packs and 66 value packs, which equaled 354354 pairs. This can be represented by the equation:\newline6r+6v=3546r + 6v = 354\newlineWhere rr is the number of pairs in a regular pack and vv is the number of pairs in a value pack.
  2. Write equations: Write the system of equations.\newline6r+4v=3126r + 4v = 312\newline6r+6v=3546r + 6v = 354
  3. Elimination method: Solve the system of equations using the elimination method.\newlineFirst, we can subtract the first equation from the second to eliminate rr.\newline(6r+6v)(6r+4v)=354312(6r + 6v) - (6r + 4v) = 354 - 312\newline6r+6v6r4v=3543126r + 6v - 6r - 4v = 354 - 312\newline2v=422v = 42
  4. Solve for vv: Solve for vv, the number of pairs in a value pack.2v=422v = 42v=422v = \frac{42}{2}v=21v = 21
  5. Substitute and solve for r: Substitute the value of vv back into one of the original equations to solve for rr. Using the first equation: 6r+4v=3126r + 4v = 312 6r+4(21)=3126r + 4(21) = 312 6r+84=3126r + 84 = 312
  6. Solve for r: Solve for r, the number of pairs in a regular pack.\newline6r+84=3126r + 84 = 312\newline6r=312846r = 312 - 84\newline6r=2286r = 228\newliner=2286r = \frac{228}{6}\newliner=38r = 38
  7. Verify solution: Verify the solution by plugging the values of rr and vv into the second equation.6r+6v=3546r + 6v = 3546(38)+6(21)=3546(38) + 6(21) = 354228+126=354228 + 126 = 354354=354354 = 354The values satisfy the second equation as well.

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