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Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.\newlineConnor and Fred got in trouble at football practice and have to run laps as a consequence. Connor, who runs at a rate of 22 laps per minute, had completed 44 laps already when he was joined on the track by Fred. Fred's pace is 66 laps per minute. At some point, the two will have run the same distance. How long will that take? How many laps will each boy have run?\newlineAfter \underline{\hspace{2em}} minutes, Connor and Fred will each have run \underline{\hspace{2em}} laps.

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Q. Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.\newlineConnor and Fred got in trouble at football practice and have to run laps as a consequence. Connor, who runs at a rate of 22 laps per minute, had completed 44 laps already when he was joined on the track by Fred. Fred's pace is 66 laps per minute. At some point, the two will have run the same distance. How long will that take? How many laps will each boy have run?\newlineAfter \underline{\hspace{2em}} minutes, Connor and Fred will each have run \underline{\hspace{2em}} laps.
  1. Define Variables: Let's define the variables:\newlineLet tt be the time in minutes after Fred starts running.\newlineLet CC be the total number of laps Connor runs.\newlineLet FF be the total number of laps Fred runs.\newlineConnor's rate is 22 laps per minute, and he has already completed 44 laps. So, Connor's total laps can be expressed as:\newlineC=2t+4C = 2t + 4
  2. Connor's Total Laps: Fred's rate is 66 laps per minute, and he starts from 00 laps. So, Fred's total laps can be expressed as:\newlineF=6tF = 6t
  3. Fred's Total Laps: We need to find the point where Connor and Fred have run the same number of laps, which means we set their total laps equal to each other: 2t+4=6t2t + 4 = 6t
  4. Set Equations Equal: Now, we solve for tt:2t+4=6t2t + 4 = 6t4=6t2t4 = 6t - 2t4=4t4 = 4tt=1t = 1
  5. Solve for t: Now that we have the time, we can find out how many laps each boy has run. We'll plug tt back into the equations for CC and FF:C=2(1)+4=2+4=6C = 2(1) + 4 = 2 + 4 = 6F=6(1)=6F = 6(1) = 6
  6. Find Laps After 11 Minute: So, after 11 minute, Connor and Fred will each have run 66 laps.

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