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Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.\newlineA camp counselor for a summer day camp sometimes buys lunch for her campers at a nearby fast food restaurant. On Monday, she purchased 11 hamburger kid meal and 33 chicken nugget kid meals, for a total of $14\$14. On Thursday, she spent $36\$36 on 44 hamburger kid meals and 77 chicken nugget kid meals. How much does each type of meal cost?\newlineEach hamburger meal costs $\$_____, and each chicken nugget meal costs $\$_____.

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Q. Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.\newlineA camp counselor for a summer day camp sometimes buys lunch for her campers at a nearby fast food restaurant. On Monday, she purchased 11 hamburger kid meal and 33 chicken nugget kid meals, for a total of $14\$14. On Thursday, she spent $36\$36 on 44 hamburger kid meals and 77 chicken nugget kid meals. How much does each type of meal cost?\newlineEach hamburger meal costs $\$_____, and each chicken nugget meal costs $\$_____.
  1. Set up equations: Set up the system of equations based on the given information.\newlineOn Monday, 11 hamburger meal (hh) and 33 chicken nugget meals (cc) cost $14\$14.\newlineOn Thursday, 44 hamburger meals (hh) and 77 chicken nugget meals (cc) cost $36\$36.\newlineThe system of equations is:\newlinehh00\newlinehh11
  2. Multiply first equation: Multiply the first equation by 44 to align the coefficient of hh with the second equation.\newline(1h+3c)×4=14×4(1h + 3c) \times 4 = 14 \times 4\newline4h+12c=564h + 12c = 56
  3. Subtract equations: Subtract the second equation from the modified first equation to eliminate hh and solve for cc.$4h+12c\$4h + 12c - 4h+7c4h + 7c = 5656 - 3636\)4h+12c4h7c=56364h + 12c - 4h - 7c = 56 - 365c=205c = 20
  4. Solve for c: Solve for c.\newline5c=205c = 20\newlinec=205c = \frac{20}{5}\newlinec=4c = 4
  5. Solve for h: Substitute the value of cc back into the original first equation to solve for hh. \newline1h+3(4)=141h + 3(4) = 14\newline1h+12=141h + 12 = 14\newline1h=14121h = 14 - 12\newlineh=2h = 2
  6. Verify solution: Verify the solution by substituting both hh and cc into the second original equation.\newline4(2)+7(4)=364(2) + 7(4) = 36\newline8+28=368 + 28 = 36\newline36=3636 = 36

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