Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.Leah owns a cake shop and she is working on two wedding cakes this week. The first cake consists of 5 small tiers and 3 large tiers, which will serve a total of 248 guests. The second one includes 2 small tiers and 1 large tier, which is enough servings for 89 guests. How many guests does each size of tier serve?A small tier will serve _ guests and a large tier will serve _ guests.
Q. Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.Leah owns a cake shop and she is working on two wedding cakes this week. The first cake consists of 5 small tiers and 3 large tiers, which will serve a total of 248 guests. The second one includes 2 small tiers and 1 large tier, which is enough servings for 89 guests. How many guests does each size of tier serve?A small tier will serve _ guests and a large tier will serve _ guests.
Set up equations: Set up the system of equations based on the given information.Leah's first cake has 5 small tiers and 3 large tiers serving 248 guests. Let's denote the number of guests served by a small tier as s and by a large tier as l. The equation for the first cake is:5s+3l=248The second cake has 2 small tiers and 1 large tier serving 89 guests. The equation for the second cake is:2s+1l=89Our system of equations is:5s+3l=2482s+1l=89
Elimination method: Solve the system of equations using the elimination method.To eliminate one of the variables, we can multiply the second equation by 3 to match the coefficient of l in the first equation:3(2s+1l)=3(89)6s+3l=267Now we have:5s+3l=2486s+3l=267Subtract the first equation from the second equation to solve for s:(6s+3l)−(5s+3l)=267−2486s−5s+3l−3l=267−248s=19
Solve for s: Substitute the value of s into one of the original equations to solve for l. Using the second equation 2s+l=89, we substitute s=19: 2(19)+l=8938+l=89l=89−38l=51
Substitute and solve: Verify the solution by substituting the values of s and l into the other equation.Using the first equation 5s+3l=248, we substitute s=19 and l=51:5(19)+3(51)=24895+153=248248=248The values s=19 and l=51 satisfy both equations.
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