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Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.\newlineLeah owns a cake shop and she is working on two wedding cakes this week. The first cake consists of 55 small tiers and 33 large tiers, which will serve a total of 248248 guests. The second one includes 22 small tiers and 11 large tier, which is enough servings for 8989 guests. How many guests does each size of tier serve?\newlineA small tier will serve _\_ guests and a large tier will serve _\_ guests.

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Q. Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.\newlineLeah owns a cake shop and she is working on two wedding cakes this week. The first cake consists of 55 small tiers and 33 large tiers, which will serve a total of 248248 guests. The second one includes 22 small tiers and 11 large tier, which is enough servings for 8989 guests. How many guests does each size of tier serve?\newlineA small tier will serve _\_ guests and a large tier will serve _\_ guests.
  1. Set up equations: Set up the system of equations based on the given information.\newlineLeah's first cake has 55 small tiers and 33 large tiers serving 248248 guests. Let's denote the number of guests served by a small tier as ss and by a large tier as ll. The equation for the first cake is:\newline5s+3l=2485s + 3l = 248\newlineThe second cake has 22 small tiers and 11 large tier serving 8989 guests. The equation for the second cake is:\newline2s+1l=892s + 1l = 89\newlineOur system of equations is:\newline5s+3l=2485s + 3l = 248\newline2s+1l=892s + 1l = 89
  2. Elimination method: Solve the system of equations using the elimination method.\newlineTo eliminate one of the variables, we can multiply the second equation by 33 to match the coefficient of ll in the first equation:\newline3(2s+1l)=3(89)3(2s + 1l) = 3(89)\newline6s+3l=2676s + 3l = 267\newlineNow we have:\newline5s+3l=2485s + 3l = 248\newline6s+3l=2676s + 3l = 267\newlineSubtract the first equation from the second equation to solve for ss:\newline(6s+3l)(5s+3l)=267248(6s + 3l) - (5s + 3l) = 267 - 248\newline6s5s+3l3l=2672486s - 5s + 3l - 3l = 267 - 248\newlines=19s = 19
  3. Solve for ss: Substitute the value of ss into one of the original equations to solve for ll. Using the second equation 2s+l=892s + l = 89, we substitute s=19s = 19: 2(19)+l=892(19) + l = 89 38+l=8938 + l = 89 l=8938l = 89 - 38 l=51l = 51
  4. Substitute and solve: Verify the solution by substituting the values of ss and ll into the other equation.\newlineUsing the first equation 5s+3l=2485s + 3l = 248, we substitute s=19s = 19 and l=51l = 51:\newline5(19)+3(51)=2485(19) + 3(51) = 248\newline95+153=24895 + 153 = 248\newline248=248248 = 248\newlineThe values s=19s = 19 and l=51l = 51 satisfy both equations.

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