Write a system of equations to describe the situation below, solve using elimination, and fill in the blanks.There are two trails near Clarence's house that he runs regularly, a short loop and a long loop. Last week, he ran 3 short loops and 4 long loops, for a total of 26 miles. This week, he ran 2 short loops and 4 long loops, covering a total of 24 miles. What is the length of each loop?The short loop has a length of _ miles, and the long loop has a length of _ miles.
Q. Write a system of equations to describe the situation below, solve using elimination, and fill in the blanks.There are two trails near Clarence's house that he runs regularly, a short loop and a long loop. Last week, he ran 3 short loops and 4 long loops, for a total of 26 miles. This week, he ran 2 short loops and 4 long loops, covering a total of 24 miles. What is the length of each loop?The short loop has a length of _ miles, and the long loop has a length of _ miles.
Define variables: Define the variables for the lengths of the short and long loops.Let x be the length of the short loop and y be the length of the long loop.
Write equations: Write the system of equations based on the given information.First week: 3 short loops and 4 long loops equal 26 miles.Second week: 2 short loops and 4 long loops equal 24 miles.This gives us the system of equations:3x+4y=262x+4y=24
Eliminate variable: Decide which variable to eliminate.We can eliminate y by subtracting the second equation from the first because the coefficients of y are the same in both equations.
Subtract equations: Subtract the second equation from the first to eliminate y.$3x+4y - 2x+4y = 26 - 24\)3x−2x+4y−4y=2x=2We have found the length of the short loop.
Substitute values: Substitute the value of x into one of the original equations to solve for y. Using the second equation: 2x+4y=242(2)+4y=244+4y=244y=24−44y=20y=20/4y=5 We have found the length of the long loop.
More problems from Solve a system of equations using elimination: word problems