Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks.\newlineIsabella wants to buy a charm bracelet. Springfield Fine Jewelry charges $13\$13 per charm, plus $64\$64 for the bracelet. Patton Jewelers, in contrast, charges $12\$12 per charm and $67\$67 for the bracelet. If Isabella wants to add a certain number of charms to her bracelet, the cost will be the same at either jewelry shop. How many charms would that be? What would the total cost of the bracelet be?\newlineIf Isabella adds _____ charms to her bracelet, it will cost $\$_____ at either shop.

Full solution

Q. Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks.\newlineIsabella wants to buy a charm bracelet. Springfield Fine Jewelry charges $13\$13 per charm, plus $64\$64 for the bracelet. Patton Jewelers, in contrast, charges $12\$12 per charm and $67\$67 for the bracelet. If Isabella wants to add a certain number of charms to her bracelet, the cost will be the same at either jewelry shop. How many charms would that be? What would the total cost of the bracelet be?\newlineIf Isabella adds _____ charms to her bracelet, it will cost $\$_____ at either shop.
  1. Define Variables: Let's define the variables:\newlineLet xx be the number of charms Isabella wants to add to her bracelet.\newlineLet yy be the total cost of the bracelet with charms at either jewelry shop.\newlineNow, we can write the equations for the total cost at each shop:\newlineSpringfield Fine Jewelry: y=13x+64y = 13x + 64\newlinePatton Jewelers: y=12x+67y = 12x + 67\newlineThe question_prompt: "How many charms would that be? What would the total cost of the bracelet be?"
  2. Write Equations: To find the number of charms for which the cost is the same at both shops, we set the two equations equal to each other:\newline13x+64=12x+6713x + 64 = 12x + 67
  3. Set Equations Equal: Now, we solve for xx by subtracting 12x12x from both sides of the equation:\newline13x12x+64=12x12x+6713x - 12x + 64 = 12x - 12x + 67\newlinex+64=67x + 64 = 67
  4. Solve for x: Next, we subtract 6464 from both sides to isolate xx: \newlinex+6464=6764x + 64 - 64 = 67 - 64\newlinex=3x = 3
  5. Substitute xx into Equation: Now that we have the number of charms (xx), we can substitute it back into either of the original equations to find the total cost (yy). Let's use the Springfield Fine Jewelry equation:\newliney=13x+64y = 13x + 64\newliney=13(3)+64y = 13(3) + 64
  6. Calculate Total Cost: We calculate the total cost:\newliney=39+64y = 39 + 64\newliney=103y = 103
  7. Final Result: We have found that if Isabella adds 33 charms to her bracelet, it will cost $103\$103 at either shop.

More problems from Solve a system of equations using substitution: word problems