Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.Dr. Thompson, a pediatrician, has 3 annual checkups and 2 sick visits scheduled next Tuesday, which will fill a total of 220 minutes on his schedule. Next Wednesday, he has 3 annual checkups and 3 sick visits on the schedule, which should take 246 minutes. How much time is allotted for each type of appointment?The time allotted is _ minutes for an annual checkup and _ minutes for a sick visit.
Q. Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.Dr. Thompson, a pediatrician, has 3 annual checkups and 2 sick visits scheduled next Tuesday, which will fill a total of 220 minutes on his schedule. Next Wednesday, he has 3 annual checkups and 3 sick visits on the schedule, which should take 246 minutes. How much time is allotted for each type of appointment?The time allotted is _ minutes for an annual checkup and _ minutes for a sick visit.
Define Equations: Let's denote the time for an annual checkup as x minutes and the time for a sick visit as y minutes.We need to set up two equations based on the information given.
Set Up Equations: For next Tuesday, the equation based on the information given is:3x (time for annual checkups) + 2y (time for sick visits) = 220 minutes.So, we have the equation: 3x+2y=220.
Solve for Variables: For next Wednesday, the equation based on the information given is: 3x (time for annual checkups) + 3y (time for sick visits) = 246 minutes.So, we have the equation: 3x+3y=246.
Substitute and Solve: We now have a system of equations:3x+2y=2203x+3y=246We can solve this system using the elimination method by subtracting the first equation from the second to eliminate x.
Final Results: Subtracting the first equation from the second gives us:(3x+3y)−(3x+2y)=246−220This simplifies to:3y−2y=26y=26
Final Results: Subtracting the first equation from the second gives us:(3x+3y)−(3x+2y)=246−220This simplifies to:3y−2y=26y=26Now that we have the value for y, we can substitute it back into one of the original equations to solve for x. Let's use the first equation:3x+2(26)=220
Final Results: Subtracting the first equation from the second gives us:(3x+3y)−(3x+2y)=246−220This simplifies to:3y−2y=26y=26Now that we have the value for y, we can substitute it back into one of the original equations to solve for x. Let's use the first equation:3x+2(26)=220Simplify and solve for x:3x+52=2203x=220−523x=1683y−2y=2603y−2y=261
Final Results: Subtracting the first equation from the second gives us:(3x+3y)−(3x+2y)=246−220This simplifies to:3y−2y=26y=26Now that we have the value for y, we can substitute it back into one of the original equations to solve for x. Let's use the first equation:3x+2(26)=220Simplify and solve for x:3x+52=2203x=220−523x=1683y−2y=2603y−2y=261We have found the values for x and y:3y−2y=261 minutes for an annual checkupy=26 minutes for a sick visitThese are the times allotted for each type of appointment.
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