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Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.\newlineFriends and family of the bride will be helping assemble centerpieces for the wedding reception. On the right side of the room, there will be 99 round tables and 1111 rectangular tables, which will require a total of 5151 centerpieces. On the left side, there will be 99 round tables and 1010 rectangular tables, for which they will need to assemble a total of 4848 centerpieces. How many centerpieces will be on each table?\newlineThere will be _\_ centerpieces on every round table and _\_ centerpieces on every rectangular one.

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Q. Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.\newlineFriends and family of the bride will be helping assemble centerpieces for the wedding reception. On the right side of the room, there will be 99 round tables and 1111 rectangular tables, which will require a total of 5151 centerpieces. On the left side, there will be 99 round tables and 1010 rectangular tables, for which they will need to assemble a total of 4848 centerpieces. How many centerpieces will be on each table?\newlineThere will be _\_ centerpieces on every round table and _\_ centerpieces on every rectangular one.
  1. Set up equations: Let's denote the number of centerpieces on every round table as rr and on every rectangular table as tt. We need to set up two equations based on the information given.\newlineOn the right side of the room, there are 99 round tables and 1111 rectangular tables requiring a total of 5151 centerpieces. This gives us the equation:\newline9r+11t=519r + 11t = 51
  2. Solve first equation: On the left side of the room, there are 99 round tables and 1010 rectangular tables needing a total of 4848 centerpieces. This gives us the second equation:\newline9r+10t=489r + 10t = 48
  3. Eliminate variable: We now have a system of two equations with two variables:\newline9r+11t=519r + 11t = 51\newline9r+10t=489r + 10t = 48\newlineTo solve this system, we can subtract the second equation from the first to eliminate 'r' and solve for 't'.\newline(9r+11t)(9r+10t)=5148(9r + 11t) - (9r + 10t) = 51 - 48\newline9r+11t9r10t=39r + 11t - 9r - 10t = 3\newlinet=3t = 3
  4. Substitute back to solve: Now that we have the value for tt, we can substitute it back into one of the original equations to solve for rr. We'll use the second equation for this purpose:\newline9r+10(3)=489r + 10(3) = 48\newline9r+30=489r + 30 = 48\newline9r=48309r = 48 - 30\newline9r=189r = 18\newliner=189r = \frac{18}{9}\newliner=2r = 2

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