Write a system of equations to describe the situation below, solve using elimination, and fill in the blanks.The receivers for the Kingwood University football team are practicing running different routes on the field. They have to run a specific distance so that the quarterback knows exactly where to throw the ball. Craig ran 10 post routes and 28 slant routes, which meant he ran a total of 374 yards. Pedro ran 12 post routes and 17 slant routes, which equaled a total of 316 yards. How long is each route?A post route is _ yards long and a slant route is _ yards long.
Q. Write a system of equations to describe the situation below, solve using elimination, and fill in the blanks.The receivers for the Kingwood University football team are practicing running different routes on the field. They have to run a specific distance so that the quarterback knows exactly where to throw the ball. Craig ran 10 post routes and 28 slant routes, which meant he ran a total of 374 yards. Pedro ran 12 post routes and 17 slant routes, which equaled a total of 316 yards. How long is each route?A post route is _ yards long and a slant route is _ yards long.
Define variables: Let's define the variables for the lengths of the routes. Let x be the length of a post route in yards, and y be the length of a slant route in yards.Craig's running distance can be represented by the equation: 10x+28y=374.Pedro's running distance can be represented by the equation: 12x+17y=316.
Write equations: Write the system of equations based on the information given.For Craig: 10x+28y=374For Pedro: 12x+17y=316
Use elimination method: To use elimination, we need to make the coefficients of one of the variables the same in both equations. We can multiply the entire first equation by 12 and the second equation by 10 to make the coefficients of x the same.Multiplying the first equation by 12: 12(10x+28y)=12(374)Multiplying the second equation by 10: 10(12x+17y)=10(316)
Perform multiplication: Perform the multiplication from Step 3.First equation after multiplication: 120x+336y=4488Second equation after multiplication: 120x+170y=3160
Subtract equations: Subtract the second equation from the first equation to eliminate x.$120x+336y - 120x+170y = 4488 - 3160\)120x+336y−120x−170y=4488−3160336y−170y=4488−3160166y=1328
Solve for y: Solve for y by dividing both sides of the equation by 166. 166166y=1661328y=8
Substitute and solve for x: Now that we have the value for y, we can substitute it back into one of the original equations to solve for x. Let's use Craig's equation: 10x+28y=374.Substitute y=8 into the equation: 10x+28(8)=374
Substitute and solve for x: Now that we have the value for y, we can substitute it back into one of the original equations to solve for x. Let's use Craig's equation: 10x+28y=374. Substitute y=8 into the equation: 10x+28(8)=374 Solve for x. 10x+224=37410x=374−22410x=150x=10150x=15
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