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Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.\newlineGymnasts training for an upcoming competition are practicing their routines for balance beam and floor exercise. During morning practice, Quinn practiced her beam routine 33 times and her floor routine 11 time, which took a total of 66 minutes. During afternoon practice, she ran through her her beam routine 22 times and her floor routine 22 times, which took a total of 88 minutes. How long is each routine?\newlineThe beam routine is _____ minutes long and the floor exercise is _____ minutes long.

Full solution

Q. Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.\newlineGymnasts training for an upcoming competition are practicing their routines for balance beam and floor exercise. During morning practice, Quinn practiced her beam routine 33 times and her floor routine 11 time, which took a total of 66 minutes. During afternoon practice, she ran through her her beam routine 22 times and her floor routine 22 times, which took a total of 88 minutes. How long is each routine?\newlineThe beam routine is _____ minutes long and the floor exercise is _____ minutes long.
  1. Define Variables: Let's define the variables for the lengths of the routines. Let xx be the length of the beam routine in minutes, and yy be the length of the floor routine in minutes.
  2. First Equation: According to the morning practice information, we can write the first equation based on the total time spent: 3x3x (beam routines) + 1y1y (floor routine) = 66 minutes.\newline3x+y=63x + y = 6
  3. Second Equation: From the afternoon practice information, we can write the second equation: 2x2x (beam routines) + 2y2y (floor routines) = 88 minutes.\newline2x+2y=82x + 2y = 8
  4. System of Equations: We now have a system of equations:\newline3x+y=63x + y = 6\newline2x+2y=82x + 2y = 8\newlineWe can solve this system using either substitution or elimination. Let's use the elimination method.
  5. Elimination Method: To eliminate yy, we can multiply the first equation by 22, so the coefficients of yy in both equations match.\newline(3x+y)×2=6×2(3x + y) \times 2 = 6 \times 2\newline6x+2y=126x + 2y = 12
  6. Eliminate y: Now we subtract the second equation from the modified first equation to eliminate y:\newline(6x+2y)(2x+2y)=128(6x + 2y) - (2x + 2y) = 12 - 8\newline6x+2y2x2y=1286x + 2y - 2x - 2y = 12 - 8\newline4x=44x = 4
  7. Subtract Equations: Solve for xx:4x=44x = 4x=44x = \frac{4}{4}x=1x = 1So, the beam routine is 11 minute long.
  8. Solve for x: Now we substitute xx back into one of the original equations to solve for yy. Let's use the first equation:\newline3x+y=63x + y = 6\newline3(1)+y=63(1) + y = 6\newline3+y=63 + y = 6
  9. Substitute xx: Solve for yy:3+y=63 + y = 6y=63y = 6 - 3y=3y = 3So, the floor routine is 33 minutes long.

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