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Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.\newlineBernie is a shoe salesman, and he works on commission. This week, there is a special incentive to sell shoes and boots by a certain company. Yesterday, Bernie sold 66 pairs of shoes and 88 pairs of boots, earning $194\$194 in commission. Today, he sold 44 pairs of shoes and 11 pair of boots, earning a total commission of $47\$47. How much does Bernie earn for the sale of each type of footwear?\newlineBernie earns $\$_____ for each pair of shoes and $\$_____ for each pair of boots.

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Q. Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.\newlineBernie is a shoe salesman, and he works on commission. This week, there is a special incentive to sell shoes and boots by a certain company. Yesterday, Bernie sold 66 pairs of shoes and 88 pairs of boots, earning $194\$194 in commission. Today, he sold 44 pairs of shoes and 11 pair of boots, earning a total commission of $47\$47. How much does Bernie earn for the sale of each type of footwear?\newlineBernie earns $\$_____ for each pair of shoes and $\$_____ for each pair of boots.
  1. Define Earnings: Let's denote the amount Bernie earns for each pair of shoes as s s and for each pair of boots as b b .
  2. Commission Calculation: According to the problem, Bernie sold 66 pairs of shoes and 88 pairs of boots yesterday, earning $194\$194 in commission. This gives us the equation:\newline6s+8b=1946s + 8b = 194
  3. System of Equations: Today, Bernie sold 44 pairs of shoes and 11 pair of boots, earning a total commission of $47\$47. This gives us the second equation:\newline4s+b=474s + b = 47
  4. Elimination Method: We now have a system of equations to solve:\newline6s+8b=1946s + 8b = 194\newline4s+b=474s + b = 47
  5. Substitute and Solve: To solve the system, we can use the substitution or elimination method. Let's use the elimination method. We can multiply the second equation by 88 to match the coefficient of b b in the first equation:\newline88(44s + b) = 88(4747)\newline3232s + 88b = 376376
  6. Substitute and Solve: To solve the system, we can use the substitution or elimination method. Let's use the elimination method. We can multiply the second equation by 88 to match the coefficient of b b in the first equation:\newline88(44s + b) = 88(4747)\newline3232s + 88b = 376376Now we subtract the first equation from the modified second equation to eliminate b b :\newline(3232s + 88b) - (66s + 88b) = 376376 - 194194\newline3232s - 66s = 376376 - 194194\newline2626s = 182182
  7. Substitute and Solve: To solve the system, we can use the substitution or elimination method. Let's use the elimination method. We can multiply the second equation by 88 to match the coefficient of b b in the first equation:\newline88(44s + b) = 88(4747)\newline3232s + 88b = 376376Now we subtract the first equation from the modified second equation to eliminate b b :\newline(3232s + 88b) - (66s + 88b) = 376376 - 194194\newline3232s - 66s = 376376 - 194194\newline2626s = 182182Divide both sides by 2626 to solve for s s :\newline2626s / 2626 = 182182 / 2626\newlines = 77
  8. Substitute and Solve: To solve the system, we can use the substitution or elimination method. Let's use the elimination method. We can multiply the second equation by 88 to match the coefficient of b b in the first equation:\newline88(44s + b) = 88(4747)\newline3232s + 88b = 376376Now we subtract the first equation from the modified second equation to eliminate b b :\newline(3232s + 88b) - (66s + 88b) = 376376 - 194194\newline3232s - 66s = 376376 - 194194\newline2626s = 182182Divide both sides by 2626 to solve for s s :\newline2626s / 2626 = 182182 / 2626\newlines = 77Now that we have the value for s s , we can substitute it back into one of the original equations to solve for b b . Let's use the second equation:\newline44s + b = 4747\newline44(77) + b = 4747\newline2828 + b = 4747
  9. Substitute and Solve: To solve the system, we can use the substitution or elimination method. Let's use the elimination method. We can multiply the second equation by 88 to match the coefficient of b b in the first equation:\newline88(44s + b) = 88(4747)\newline3232s + 88b = 376376Now we subtract the first equation from the modified second equation to eliminate b b :\newline(3232s + 88b) - (66s + 88b) = 376376 - 194194\newline3232s - 66s = 376376 - 194194\newline2626s = 182182Divide both sides by 2626 to solve for s s :\newline2626s / 2626 = 182182 / 2626\newlines = 77Now that we have the value for s s , we can substitute it back into one of the original equations to solve for b b . Let's use the second equation:\newline44s + b = 4747\newline44(77) + b = 4747\newline2828 + b = 4747Subtract 2828 from both sides to solve for b b :\newlineb = 4747 - 2828\newlineb = 1919

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