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Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.\newlineJanelle and Duncan are comparing the international calling plans on their cell phones. On her plan, Janelle pays $1\$1 just to place a call and $5\$5 for each minute. When Duncan makes an international call, he pays $5\$5 to place the call and $1\$1 for each minute. A call of a certain duration would cost exactly the same under both plans. What is the duration? What is the cost?\newlineA call of __\_\_ minutes would cost $__\$\_\_ under each plan.

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Q. Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.\newlineJanelle and Duncan are comparing the international calling plans on their cell phones. On her plan, Janelle pays $1\$1 just to place a call and $5\$5 for each minute. When Duncan makes an international call, he pays $5\$5 to place the call and $1\$1 for each minute. A call of a certain duration would cost exactly the same under both plans. What is the duration? What is the cost?\newlineA call of __\_\_ minutes would cost $__\$\_\_ under each plan.
  1. Define Variables: Let's define the variables: let xx be the duration of the call in minutes, and let yy be the total cost of the call for each plan. We need to set up two equations based on the information given for Janelle and Duncan's calling plans.\newlineJanelle's plan: Cost = $1\$1 (to place a call) + $5/minute×x\$5/\text{minute} \times x (duration)\newlineDuncan's plan: Cost = $5\$5 (to place a call) + $1/minute×x\$1/\text{minute} \times x (duration)\newlineSince the cost is the same for both plans, we can equate the two expressions for cost.
  2. Set Up Equations: Now we write the system of equations based on the above information:\newlineFor Janelle: y=1+5xy = 1 + 5x\newlineFor Duncan: y=5+xy = 5 + x\newlineSince the costs are the same, we can set the two equations equal to each other:\newline1+5x=5+x1 + 5x = 5 + x
  3. Write System of Equations: Next, we solve for xx by subtracting xx from both sides of the equation:\newline1+5xx=5+xx1 + 5x - x = 5 + x - x\newline1+4x=51 + 4x = 5
  4. Solve for x: Now, we subtract 11 from both sides to isolate the term with xx: \newline1+4x1=511 + 4x - 1 = 5 - 1\newline4x=44x = 4
  5. Substitute xx to Find yy: To find the value of xx, we divide both sides by 44:4x4=44\frac{4x}{4} = \frac{4}{4}x=1x = 1
  6. Substitute xx to Find yy: To find the value of xx, we divide both sides by 44:
    4x4=44\frac{4x}{4} = \frac{4}{4}
    x=1x = 1Now that we have the duration (xx), we can find the cost (yy) by substituting xx back into either of the original equations. Let's use Janelle's equation:
    y=1+5xy = 1 + 5x
    yy00
    yy11
    yy22

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