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Write a system of equations to describe the situation below, solve using an augmented matrix, and fill in the blanks.\newlineSubstitute teachers with Newberg School District get paid by the day, although subs with teaching credentials earn a different amount than subs without credentials. Yesterday, 11 non-credentialed sub taught in the district. That cost the district $65\$65. Today, 88 non-credentialed subs and 44 credentialed subs taught, receiving $864\$864 from the district. How much do subs get paid?\newlineSubs without credentials get paid $\$_____ per day, and subs with credentials get paid $\$_____ per day.

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Q. Write a system of equations to describe the situation below, solve using an augmented matrix, and fill in the blanks.\newlineSubstitute teachers with Newberg School District get paid by the day, although subs with teaching credentials earn a different amount than subs without credentials. Yesterday, 11 non-credentialed sub taught in the district. That cost the district $65\$65. Today, 88 non-credentialed subs and 44 credentialed subs taught, receiving $864\$864 from the district. How much do subs get paid?\newlineSubs without credentials get paid $\$_____ per day, and subs with credentials get paid $\$_____ per day.
  1. Define Daily Pay: Let's call the daily pay for non-credentialed subs xx and for credentialed subs yy.\newlineFirst situation: 11 non-credentialed sub for $65\$65.\newline1x+0y=651x + 0y = 65
  2. First Situation: Second situation: 88 non-credentialed subs and 44 credentialed subs for $864\$864.8x+4y=8648x + 4y = 864
  3. Second Situation: Now we have the system of equations:\newline1x+0y=651x + 0y = 65\newline8x+4y=8648x + 4y = 864\newlineWe'll solve this using an augmented matrix.
  4. Create Augmented Matrix: Write the augmented matrix for the system:\newline\begin{array}{cc|c} 1 & 0 & 65 \ 8 & 4 & 864 \end{array}
  5. Eliminate Variable xx: To make calculations easier, let's multiply the first row by 8-8 and add it to the second row to eliminate xx from the second equation.\newline8×[1065]=[80520]-8 \times [1 0 | 65] = [-8 0 | -520]\newline[84864]+[80520]=[04344][8 4 | 864] + [-8 0 | -520] = [0 4 | 344]
  6. Solve for Variable yy: Now the matrix looks like this:\newline1amp;0amp;amp;65 0amp;4amp;amp;344\begin{matrix} 1 & 0 & | & 65 \ 0 & 4 & | & 344 \end{matrix}\newlineDivide the second row by 44 to solve for yy.\newline0amp;4amp;amp;3444=0amp;1amp;amp;86\frac{\begin{matrix} 0 & 4 & | & 344 \end{matrix}}{4} = \begin{matrix} 0 & 1 & | & 86 \end{matrix}
  7. Substitute to Solve for x: The new matrix is:\newline1amp;0amp;amp;65 0amp;1amp;amp;86\begin{matrix} 1 & 0 & | & 65 \ 0 & 1 & | & 86 \end{matrix}\newlineThis tells us that y=86y = 86.
  8. Substitute to Solve for x: The new matrix is:\newline1amp;0amp;amp;65 0amp;1amp;amp;86\begin{matrix} 1 & 0 & | & 65 \ 0 & 1 & | & 86 \end{matrix}\newlineThis tells us that y=86y = 86.Substitute y=86y = 86 back into the first equation to solve for x.\newline1x+0(86)=651x + 0(86) = 65\newlinex=65x = 65

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