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Write a system of equations to describe the situation below, solve using an augmented matrix, and fill in the blanks.\newlineTwo coworkers picked up some writing instruments at the office supply store. Olivia selected 11 box of pencils, paying $2\$2. Next, Grayson spent $18\$18 on 66 boxes of pencils and 22 boxes of ballpoint pens. How much does a box of each cost?\newlineA box of pencils costs $____\$\_\_\_\_, and a box of pens costs $____\$\_\_\_\_.

Full solution

Q. Write a system of equations to describe the situation below, solve using an augmented matrix, and fill in the blanks.\newlineTwo coworkers picked up some writing instruments at the office supply store. Olivia selected 11 box of pencils, paying $2\$2. Next, Grayson spent $18\$18 on 66 boxes of pencils and 22 boxes of ballpoint pens. How much does a box of each cost?\newlineA box of pencils costs $____\$\_\_\_\_, and a box of pens costs $____\$\_\_\_\_.
  1. Define Variables: Let xx be the cost of a box of pencils and yy be the cost of a box of pens. Olivia's purchase gives us the equation: 1x=21x = 2.
  2. Olivia's Equation: Grayson's purchase gives us the equation: 6x+2y=186x + 2y = 18.
  3. Grayson's Equation: We now have the system of equations:\newline1x+0y=21x + 0y = 2\newline6x+2y=186x + 2y = 18
  4. Create Augmented Matrix: To solve using an augmented matrix, write the coefficients in matrix form: [1amp;0amp;amp;2 6amp;2amp;amp;18]\begin{bmatrix} 1 & 0 & \vert & 2 \ 6 & 2 & \vert & 18 \end{bmatrix}
  5. Row Operations: Perform row operations to get the leading coefficient of the first row to be 11. It's already 11, so no operation is needed on the first row.
  6. Make Leading Coefficient 11: Next, make the first coefficient of the second row 00 by replacing R2R_2 with R26R1R_2 - 6\cdot R_1:\newline \begin{array}{cc|c} 1 & 0 & 2 \ 0 & 2 & 12 \end{array}
  7. Divide Second Row: Now, divide the second row by 22 to get the leading coefficient to be 11: \newline\begin{array}{cc|c} 1 & 0 & 2 \ 0 & 1 & 6 \end{array}
  8. Read Solutions: We can now read the solutions from the matrix: x=2x = 2 and y=6y = 6. But wait, let's check if this is correct by plugging the values back into the original equations.
  9. Check First Equation: Check with the first equation: 1x=21x = 2. Plugging in x=2x = 2 gives us 1(2)=21(2) = 2, which is true.
  10. Check Second Equation: Check with the second equation: 6x+2y=186x + 2y = 18. Plugging in x=2x = 2 and y=6y = 6 gives us 6(2)+2(6)=12+12=246(2) + 2(6) = 12 + 12 = 24, which is not equal to 1818. There's a mistake.

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