Write a system of equations to describe the situation below, solve using an augmented matrix, and fill in the blanks.Two fifth grade classes are attending an amusement park as a field trip. Their teachers purchased the tickets for the class and the parent chaperones. Mrs. Randolph purchased 30 child tickets and 23 adult tickets, which cost a total of $1,359. Mr. Kent purchased 1 adult ticket, paying a total of $33. What are the ticket prices?The price of a child ticket is $____ and the price of an adult ticket is $____.
Q. Write a system of equations to describe the situation below, solve using an augmented matrix, and fill in the blanks.Two fifth grade classes are attending an amusement park as a field trip. Their teachers purchased the tickets for the class and the parent chaperones. Mrs. Randolph purchased 30 child tickets and 23 adult tickets, which cost a total of $1,359. Mr. Kent purchased 1 adult ticket, paying a total of $33. What are the ticket prices?The price of a child ticket is $____ and the price of an adult ticket is $____.
Define Variables: Let x be the price of a child ticket and y be the price of an adult ticket.Mrs. Randolph's purchase: 30x+23y=1359Mr. Kent's purchase: x+y=33
Create Augmented Matrix: Write the system of equations as an augmented matrix:\begin{array}{cc|c}
30 & 23 & 1359 \
1 & 1 & 33
\end{array}
Transform to Row-Echelon Form: Use row operations to transform the matrix into row-echelon form.First, swap the rows so the smaller coefficient of x is in the top row.\begin{align*}\(\newline&\begin{array}{cc|c}1 & 1 & 33 (\newline\)30 & 23 & 1359\end{array}\end{align*}\)
Eliminate Variable x: Multiply the first row by −30 and add it to the second row to eliminate x from the second row.−30×(11∣33)+(3023∣1359)=(0−7∣−33+1359)This results in the new second row: (0−7∣1326)
Solve for Variable y: Divide the second row by −7 to solve for y.(0−7∣1326)/−7=(01∣−189)This gives us y=−189, which is incorrect because ticket prices can't be negative.
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