Will factored 7x^(6) as (3x^(2))(4x^(4)). Olivia factored 7x^(6) as (7x^(2))(x^(3)). Which of them factored 7x^(6) correctly? Choose 1 answer: (A) Only Will (B) Only Olivia (C) Both Will and Olivia (D) Neither Will nor Olivia

Analyze Will's method: Analyze Will's factoring method. Will factored 7x^(6) as (3x^(2))(4x^(4)). To check if this is correct, we multiply the two factors together. (3x^(2))(4x^(4)) = 12x^(6) This is not equal to 7x^(6) because the coefficient is 12 instead of 7.Analyze Olivia's method: Analyze Olivia's factoring method. Olivia factored 7x^(6) as (7x^(2))(x^(3)). To check if this is correct, we multiply the two factors together. (7x^(2))(x^(3)) = 7x^(5) This is not equal to 7x^(6) because the exponent is 5 instead of 6.Determine correct factoring: Determine the correct factoring. Since neither Will's nor Olivia's factoring methods resulted in 7x^(6), neither of them factored 7x^(6) correctly.

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Will factored
7x^(6) as
(3x^(2))(4x^(4)).
Olivia factored
7x^(6) as
(7x^(2))(x^(3)).
Which of them factored
7x^(6) correctly?
Choose 1 answer:
(A) Only Will
(B) Only Olivia
(C) Both Will and Olivia
(D) Neither Will nor Olivia

Will factored $7x^{6}$ as $\newline$ $(3x^{2})(4x^{4})$ . $\newline$ Olivia factored $7x^{6}$ as $\newline$ $(7x^{2})(x^{3})$ . $\newline$ Which of them factored $7x^{6}$ correctly? $\newline$ Choose $1$ answer: $\newline$ (A) Only Will $\newline$ (B) Only Olivia $\newline$ (C) Both Will and Olivia $\newline$ (D) Neither Will nor Olivia

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Math Problems

Algebra 1

Transformations of quadratic functions

Full solution

Q. Will factored

7x^{6}

\newline

(3x^{2})(4x^{4})

\newline

Olivia factored

7x^{6}

\newline

(7x^{2})(x^{3})

\newline

Which of them factored

7x^{6}

correctly?

\newline

Choose

1

answer:

\newline

(A) Only Will

\newline

(B) Only Olivia

\newline

\newline

(D) Neither Will nor Olivia

Analyze Will's method: Analyze Will's factoring method. $\newline$ Will factored $7x^{6}$ as $(3x^{2})(4x^{4})$ . To check if this is correct, we multiply the two factors together. $\newline$ $(3x^{2})(4x^{4}) = 12x^{6}$ $\newline$ This is not equal to $7x^{6}$ because the coefficient is $12$ instead of $7$ .
Analyze Olivia's method: Analyze Olivia's factoring method. Olivia factored $7x^{6}$ as $(7x^{2})(x^{3})$ . To check if this is correct, we multiply the two factors together. $(7x^{2})(x^{3}) = 7x^{5}$ This is not equal to $7x^{6}$ because the exponent is $5$ instead of $6$ .
Determine correct factoring: Determine the correct factoring. $\newline$ Since neither Will's nor Olivia's factoring methods resulted in $7x^{6}$ , neither of them factored $7x^{6}$ correctly.