Q. Which value of x satisfies the equation 23(x+25)=433 ?−2−323
Multiply by 2: Given the equation (23)(x+(25))=(433), we need to solve for x. First, we simplify the equation by multiplying both sides by 2 to get rid of the fraction on the left side.(3)(x+(25))=(433)×2
Simplify right side: Now we simplify the right side of the equation by multiplying 33 by 2 and then dividing by 4. (3)(x+25)=466 (3)(x+25)=16.5
Distribute 3: Next, we distribute the 3 on the left side of the equation.3x+(3×25)=16.53x+215=16.5
Convert to fraction: To simplify further, we convert 16.5 to a fraction to have a common denominator with (15)/(2). 3x+(15)/(2)=(33)/(2)
Subtract (15)/(2): Now we subtract (15)/(2) from both sides to isolate the term with x.3x=233−2153x=233−15
Perform subtraction: We perform the subtraction in the numerator.3x=2183x=9
Divide by 3: Finally, we divide both sides by 3 to solve for x.x=39x=3
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