Q. Which type of conic section is defined by the equation 4x2−16y2+16x−160y−448=0 ?This is an equation of
Simplify Equation: Step 1: Simplify the equation by grouping similar terms. 4x2+16x−16y2−160y−448=0
Rearrange for Identification: Step 2: Rearrange the equation to make it easier to identify. 4x2+16x−16y2−160y=448
Divide and Simplify: Step 3: Divide the entire equation by 4 to simplify.x2+4x−4y2−40y=112
Complete the Square: Step 4: Complete the square for the x-terms and y-terms.(x2+4x)−4(y2+10y)=112Adding and subtracting 4 inside the first parenthesis and 100 inside the second parenthesis:(x2+4x+4−4)−4(y2+10y+25−25)=112(x+2)2−4−4((y+5)2−25)=112(x+2)2−4(y+5)2+100=112
Further Simplification: Step 5: Simplify the equation further.(x+2)2−4(y+5)2=12
Identify Conic Section: Step 6: Identify the type of conic section.The equation (x+2)2−4(y+5)2=12 is in the form of a hyperbola because it has one squared term subtracted from another squared term.
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