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Which statement best describes the limit shown below?

lim_(x rarr oo)(x^(19))/(2x^(19)-10e^(x))
The limit equals zero
The limit does not exist
The limit exists and does not equal zero

Which statement best describes the limit shown below?\newlinelimxx192x1910ex \lim _{x \rightarrow \infty} \frac{x^{19}}{2 x^{19}-10 e^{x}} \newlineThe limit equals zero\newlineThe limit does not exist\newlineThe limit exists and does not equal zero

Full solution

Q. Which statement best describes the limit shown below?\newlinelimxx192x1910ex \lim _{x \rightarrow \infty} \frac{x^{19}}{2 x^{19}-10 e^{x}} \newlineThe limit equals zero\newlineThe limit does not exist\newlineThe limit exists and does not equal zero
  1. Analyze Highest Degree Terms: We are given the limit expression limx(x192x1910ex)\lim_{x \to \infty}\left(\frac{x^{19}}{2x^{19} - 10e^{x}}\right). To find the behavior of this function as xx approaches infinity, we need to analyze the highest degree terms in the numerator and the denominator.
  2. Exponential Term Dominance: In the numerator, we have x19x^{19}, and in the denominator, we have 2x192x^{19} and 10ex-10e^{x}. As xx approaches infinity, the exponential term exe^{x} grows much faster than any polynomial term, including x19x^{19}.
  3. Denominator Control: Since exe^{x} grows faster than x19x^{19}, the term 10ex-10e^{x} in the denominator will dominate over 2x192x^{19} as xx approaches infinity. This means that the denominator will essentially be controlled by the 10ex-10e^{x} term.
  4. Approaching Zero: Given that the exponential term dominates and grows without bound, the fraction x192x1910ex\frac{x^{19}}{2x^{19} - 10e^{x}} will approach zero as xx approaches infinity. This is because the numerator grows at a polynomial rate, while the denominator grows at an exponential rate.
  5. Limit Statement: Therefore, the correct statement that describes the limit is: "The limit equals 00."

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