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Which statement best describes the limit shown below?

lim_(x rarr oo)(9x^(61))/(-9x^(61)+x^(60))
The limit equals zero
The limit does not exist
The limit exists and does not equal zero

Which statement best describes the limit shown below?\newlinelimx9x619x61+x60 \lim _{x \rightarrow \infty} \frac{9 x^{61}}{-9 x^{61}+x^{60}} \newlineThe limit equals zero\newlineThe limit does not exist\newlineThe limit exists and does not equal zero

Full solution

Q. Which statement best describes the limit shown below?\newlinelimx9x619x61+x60 \lim _{x \rightarrow \infty} \frac{9 x^{61}}{-9 x^{61}+x^{60}} \newlineThe limit equals zero\newlineThe limit does not exist\newlineThe limit exists and does not equal zero
  1. Identify Powers: We are given the limit expression limx(9x61)/(9x61+x60)\lim_{x \to \infty}(9x^{61})/(-9x^{61}+x^{60}). To find the limit as xx approaches infinity, we need to analyze the behavior of the numerator and the denominator separately.
  2. Factor Out x61x^{61}: First, let's look at the highest power of xx in both the numerator and the denominator. In this case, the highest power of xx is 6161 in both terms.
  3. Simplify Expression: We can factor out x61x^{61} from both the numerator and the denominator to simplify the expression. This gives us:\newlinelimx9x619x61+x60=limx911x\lim_{x \to \infty}\frac{9x^{61}}{-9x^{61}+x^{60}} = \lim_{x \to \infty}\frac{9}{1 - \frac{1}{x}}
  4. Evaluate Limit: As xx approaches infinity, the term (1/x)(1/x) approaches zero. Therefore, the expression simplifies to: limx(91(1x))=910=91=9\lim_{x \to \infty}\left(\frac{9}{1 - \left(\frac{1}{x}\right)}\right) = \frac{9}{1 - 0} = \frac{9}{1} = 9
  5. Final Conclusion: The limit exists and does not equal 00. The correct statement is "The limit exists and does not equal 00."

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