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Which statement best describes the limit shown below?

lim_(x rarr oo)(x^(68))/(6x^(68)+x^(62))
The limit equals zero
The limit does not exist
The limit exists and does not equal zero

Which statement best describes the limit shown below?\newlinelimxx686x68+x62 \lim _{x \rightarrow \infty} \frac{x^{68}}{6 x^{68}+x^{62}} \newlineThe limit equals zero\newlineThe limit does not exist\newlineThe limit exists and does not equal zero

Full solution

Q. Which statement best describes the limit shown below?\newlinelimxx686x68+x62 \lim _{x \rightarrow \infty} \frac{x^{68}}{6 x^{68}+x^{62}} \newlineThe limit equals zero\newlineThe limit does not exist\newlineThe limit exists and does not equal zero
  1. Analyze Degree Comparison: We are given the limit expression limx(x686x68+x62)\lim_{x \to \infty}\left(\frac{x^{68}}{6x^{68} + x^{62}}\right). To find the limit as xx approaches infinity, we can compare the degrees of the polynomials in the numerator and the denominator.
  2. Divide by Highest Degree Term: Since the highest degree term in both the numerator and the denominator is x68x^{68}, we can divide every term by x68x^{68} to simplify the expression.\newlinelimxx686x68+x62=limx16+x62x68\lim_{x \to \infty}\frac{x^{68}}{6x^{68} + x^{62}} = \lim_{x \to \infty}\frac{1}{6 + \frac{x^{62}}{x^{68}}}
  3. Simplify Expression: Simplify the expression inside the limit by canceling out x62x^{62} from the denominator's second term.\newlinelimx(16+x62x68)=limx(16+1x6)\lim_{x \to \infty}\left(\frac{1}{6 + \frac{x^{62}}{x^{68}}}\right) = \lim_{x \to \infty}\left(\frac{1}{6 + \frac{1}{x^{6}}}\right)
  4. Negligible Term Removal: As xx approaches infinity, 1x6\frac{1}{x^{6}} approaches 00. Therefore, the term 1x6\frac{1}{x^{6}} in the denominator becomes negligible.\newlinelimx16+1x6=limx16+0\lim_{x \to \infty}\frac{1}{6 + \frac{1}{x^{6}}} = \lim_{x \to \infty}\frac{1}{6 + 0}
  5. Final Simplification: Simplify the expression by removing the term that approaches zero.\newlinelimx(16+0)=16\lim_{x \to \infty}(\frac{1}{6 + 0}) = \frac{1}{6}
  6. Limit Result: The limit of the function as xx approaches infinity is 16\frac{1}{6}, which is a finite number and does not equal zero.

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