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Which statement best describes the limit shown below?

lim_(x rarr oo)(x^(10))/(-2x^(10)-8log_(3)x)
The limit equals zero
The limit does not exist
The limit exists and does not equal zero

Which statement best describes the limit shown below?\newlinelimxx102x108log3x \lim _{x \rightarrow \infty} \frac{x^{10}}{-2 x^{10}-8 \log _{3} x} \newlineThe limit equals zero\newlineThe limit does not exist\newlineThe limit exists and does not equal zero

Full solution

Q. Which statement best describes the limit shown below?\newlinelimxx102x108log3x \lim _{x \rightarrow \infty} \frac{x^{10}}{-2 x^{10}-8 \log _{3} x} \newlineThe limit equals zero\newlineThe limit does not exist\newlineThe limit exists and does not equal zero
  1. Given Limit Expression: We are given the limit expression:\newlinelimxx102x108log3x\lim_{x \rightarrow \infty}\frac{x^{10}}{-2x^{10}-8\log_{3}x}\newlineTo find the limit as xx approaches infinity, we need to analyze the behavior of the numerator and the denominator separately.
  2. Highest Power Analysis: First, let's focus on the highest power of xx in both the numerator and the denominator. In the numerator, the highest power is x10x^{10}. In the denominator, the highest power is also x10x^{10}, which is in the term 2x10-2x^{10}.
  3. Simplify by Dividing: Since the highest power of xx in both the numerator and the denominator is the same, we can simplify the expression by dividing both the numerator and the denominator by x10x^{10}.limxx10/x102x10/x108log3x/x10\lim_{x \rightarrow \infty}\frac{x^{10}/x^{10}}{-2x^{10}/x^{10}-8\log_{3}x/x^{10}}
  4. Limit as x Approaches Infinity: Simplifying the expression, we get:\newlinelimx128log3x/x10\lim_{x \rightarrow \infty}\frac{1}{-2-8\log_{3}x/x^{10}}\newlineAs x approaches infinity, the term 8log3xx10\frac{8\log_{3}x}{x^{10}} approaches zero because the logarithmic function grows much slower than the polynomial function.
  5. Simplify Limit: Now, the limit simplifies to: \newlinelimx120\lim_{x \rightarrow \infty}\frac{1}{-2-0}\newlineWhich is simply: \newlinelimx12\lim_{x \rightarrow \infty}\frac{1}{-2}
  6. Final Result: The limit of a constant over a constant is just the division of those constants. Therefore, the limit is: 1(2)=12\frac{1}{(-2)} = -\frac{1}{2}
  7. Conclusion: Since we have found a finite value for the limit, the correct statement is that the limit exists and does not equal 00.

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