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Which statement best describes the limit shown below?

lim_(x rarr oo)(-3x^(23)+4^(x))/(3log_(4)x-5x^(8))
The limit equals zero
The limit does not exist
The limit exists and does not equal zero

Which statement best describes the limit shown below?\newlinelimx3x23+4x3log4x5x8 \lim _{x \rightarrow \infty} \frac{-3 x^{23}+4^{x}}{3 \log _{4} x-5 x^{8}} \newlineThe limit equals zero\newlineThe limit does not exist\newlineThe limit exists and does not equal zero

Full solution

Q. Which statement best describes the limit shown below?\newlinelimx3x23+4x3log4x5x8 \lim _{x \rightarrow \infty} \frac{-3 x^{23}+4^{x}}{3 \log _{4} x-5 x^{8}} \newlineThe limit equals zero\newlineThe limit does not exist\newlineThe limit exists and does not equal zero
  1. Given Limit Expression: We are given the limit expression:\newline\lim_{x \to \infty}(\-3x^{23} + 4^{x}) / (3\log_{4}x - 5x^{8})\newlineTo find the behavior of this function as xx approaches infinity, we need to determine the dominant terms in the numerator and the denominator.
  2. Determining Dominant Terms: In the numerator, the dominant term is 3x23-3x^{23} because as xx approaches infinity, x23x^{23} will grow much faster than 4x4^{x}, which is exponential but does not depend on xx in the base.\newlineIn the denominator, the dominant term is 5x8-5x^{8} because as xx approaches infinity, x8x^{8} will grow much faster than the logarithmic term 3log4x3\log_{4}x.\newlineSo, we can simplify the limit to focus on the dominant terms in the numerator and the denominator:\newlinelimx(3x235x8)\lim_{x \to \infty}(\frac{-3x^{23}}{-5x^{8}})
  3. Simplifying the Limit: Now, we simplify the expression by dividing the coefficients and subtracting the exponents of xx:(3/5)×x(238)=(3/5)×x15(-3/-5) \times x^{(23-8)} = (3/5) \times x^{15} As xx approaches infinity, x15x^{15} will also approach infinity. Therefore, the limit of the simplified expression as xx approaches infinity is also infinity.
  4. Final Limit Evaluation: Since the limit of the simplified expression is \infty, the original limit also approaches \infty. This means that the limit does not equal 00 and it does exist, but it does not equal a finite number.\newlineTherefore, the correct statement is: The limit exists and does not equal 00.

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