Which set of ordered pairs does not represent a function? {(-3,5),(-4,2),(-8,-1),(-6,5)} {(-8,3),(9,4),(8,1),(3,-2)} {(5,9),(3,-9),(-5,3),(3,-8)} {(9,-8),(-3,3),(-6,-3),(1,-8)}

Define function as relation: A function is defined as a relation where each input (x-value) has exactly one output (y-value). To determine which set of ordered pairs does not represent a function, we need to check if there are any repeated x-values with different y-values in each set.Check first set: Let's examine the first set: {(-3,5),(-4,2),(-8,-1),(-6,5)}. We need to check if any x-value is repeated with a different y-value.Check second set: In the first set, all x-values are unique: -3, -4, -8, and -6. Since there are no repeated x-values, this set represents a function.Check third set: Now, let's examine the second set: {(-8,3),(9,4),(8,1),(3,-2)}. Again, we check for any repeated x-values with different y-values.Final decision: In the second set, all x-values are unique: -8, 9, 8, and 3. Since there are no repeated x-values, this set also represents a function.Next, let's examine the third set: {(5,9),(3,-9),(-5,3),(3,-8)}. We look for any repeated x-values with different y-values.In the third set, the x-value 3 is repeated with different y-values: (3,-9) and (3,-8). This means that for the same input, there are two different outputs, which violates the definition of a function.Since the third set has a repeated x-value with different y-values, it does not represent a function. We do not need to check the fourth set, as we have already found the set that does not represent a function.

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Which set of ordered pairs does not represent a function?

{(-3,5),(-4,2),(-8,-1),(-6,5)}

{(-8,3),(9,4),(8,1),(3,-2)}

{(5,9),(3,-9),(-5,3),(3,-8)}

{(9,-8),(-3,3),(-6,-3),(1,-8)}

Which set of ordered pairs does not represent a function? $\newline$ $\{(-3,5),(-4,2),(-8,-1),(-6,5)\}$ $\newline$ $\{(-8,3),(9,4),(8,1),(3,-2)\}$ $\newline$ $\{(5,9),(3,-9),(-5,3),(3,-8)\}$ $\newline$ $\{(9,-8),(-3,3),(-6,-3),(1,-8)\}$

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Math Problems

Algebra 1

Write a quadratic function from its x-intercepts and another point

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Q. Which set of ordered pairs does not represent a function?

\newline

\{(-3,5),(-4,2),(-8,-1),(-6,5)\}

\newline

\{(-8,3),(9,4),(8,1),(3,-2)\}

\newline

\{(5,9),(3,-9),(-5,3),(3,-8)\}

\newline

\{(9,-8),(-3,3),(-6,-3),(1,-8)\}

Define function as relation: A function is defined as a relation where each input ( extit{x}-value) has exactly one output ( extit{y}-value). To determine which set of ordered pairs does not represent a function, we need to check if there are any repeated extit{x}-values with different extit{y}-values in each set.
Check first set: Let's examine the first set: $\{(-3,5),(-4,2),(-8,-1),(-6,5)\}$ . We need to check if any $x$ -value is repeated with a different $y$ -value.
Check second set: In the first set, all $x$ -values are unique: $-3$ , $-4$ , $-8$ , and $-6$ . Since there are no repeated $x$ -values, this set represents a function.
Check third set: Now, let's examine the second set: $\{(-8,3),(9,4),(8,1),(3,-2)\}$ . Again, we check for any repeated $x$ -values with different $y$ -values.
Final decision: In the second set, all $x$ -values are unique: $-8$ , $9$ , $8$ , and $3$ . Since there are no repeated $x$ -values, this set also represents a function.
Final decision: In the second set, all $x$ -values are unique: $-8$ , $9$ , $8$ , and $3$ . Since there are no repeated $x$ -values, this set also represents a function.Next, let's examine the third set: $\{(5,9),(3,-9),(-5,3),(3,-8)\}$ . We look for any repeated $x$ -values with different $y$ -values.
Final decision: In the second set, all $x$ -values are unique: $-8$ , $9$ , $8$ , and $3$ . Since there are no repeated $x$ -values, this set also represents a function.Next, let's examine the third set: $\{(5,9),(3,-9),(-5,3),(3,-8)\}$ . We look for any repeated $x$ -values with different $y$ -values.In the third set, the $x$ -value $3$ is repeated with different $y$ -values: $-8$ $2$ and $-8$ $3$ . This means that for the same input, there are two different outputs, which violates the definition of a function.
Final decision: In the second set, all $x$ -values are unique: $-8$ , $9$ , $8$ , and $3$ . Since there are no repeated $x$ -values, this set also represents a function.Next, let's examine the third set: $\{(5,9),(3,-9),(-5,3),(3,-8)\}$ . We look for any repeated $x$ -values with different $y$ -values.In the third set, the $x$ -value $3$ is repeated with different $y$ -values: $-8$ $2$ and $-8$ $3$ . This means that for the same input, there are two different outputs, which violates the definition of a function.Since the third set has a repeated $x$ -value with different $y$ -values, it does not represent a function. We do not need to check the fourth set, as we have already found the set that does not represent a function.