Which set of ordered pairs does not represent a function? {(2,9),(4,-6),(4,-7),(8,4)} {(5,-1),(-8,-3),(8,6),(-7,-1)} {(5,5),(1,9),(3,9),(-7,0)} {(5,1),(0,-2),(1,1),(-1,-4)}

Check Function Criteria: To determine if a set of ordered pairs represents a function, we need to check if each input (x-value) maps to exactly one output (y-value). A function cannot have the same input paired with different outputs.Examine First Set: Let's examine the first set of ordered pairs: {(2,9),(4,-6),(4,-7),(8,4)}. We notice that the input 4 is paired with two different outputs: -6 and -7. This violates the definition of a function.Conclusion: Since we have found that the input 4 has two different outputs in the first set, we can conclude that this set does not represent a function.

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Which set of ordered pairs does not represent a function?

{(2,9),(4,-6),(4,-7),(8,4)}

{(5,-1),(-8,-3),(8,6),(-7,-1)}

{(5,5),(1,9),(3,9),(-7,0)}

{(5,1),(0,-2),(1,1),(-1,-4)}

Which set of ordered pairs does not represent a function? $\newline$ $\{(2,9),(4,-6),(4,-7),(8,4)\}$ $\newline$ $\{(5,-1),(-8,-3),(8,6),(-7,-1)\}$ $\newline$ $\{(5,5),(1,9),(3,9),(-7,0)\}$ $\newline$ $\{(5,1),(0,-2),(1,1),(-1,-4)\}$

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Math Problems

Algebra 1

Write a quadratic function from its x-intercepts and another point

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Q. Which set of ordered pairs does not represent a function?

\newline

\{(2,9),(4,-6),(4,-7),(8,4)\}

\newline

\{(5,-1),(-8,-3),(8,6),(-7,-1)\}

\newline

\{(5,5),(1,9),(3,9),(-7,0)\}

\newline

\{(5,1),(0,-2),(1,1),(-1,-4)\}

Check Function Criteria: To determine if a set of ordered pairs represents a function, we need to check if each input ( $x$ -value) maps to exactly one output ( $y$ -value). A function cannot have the same input paired with different outputs.
Examine First Set: Let's examine the first set of ordered pairs: ${(2,9),(4,-6),(4,-7),(8,4)}$ . We notice that the input $4$ is paired with two different outputs: $-6$ and $-7$ . This violates the definition of a function.
Conclusion: Since we have found that the input $4$ has two different outputs in the first set, we can conclude that this set does not represent a function.