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Which recursive formula can be used to define this sequence for n > 1?\newline1,12,23,34,45,56,1, 12, 23, 34, 45, 56, \ldots\newlineChoices:\newline(A) an=an1+11a_n = a_{n-1} + 11\newline(B) an=176an1a_n = \frac{17}{6}a_{n-1}\newline(C) an=an1+an1+11a_n = a_{n-1} + a_{n-1} + 11\newline(D) an=an111a_n = a_{n-1} - 11

Full solution

Q. Which recursive formula can be used to define this sequence for n>1n > 1?\newline1,12,23,34,45,56,1, 12, 23, 34, 45, 56, \ldots\newlineChoices:\newline(A) an=an1+11a_n = a_{n-1} + 11\newline(B) an=176an1a_n = \frac{17}{6}a_{n-1}\newline(C) an=an1+an1+11a_n = a_{n-1} + a_{n-1} + 11\newline(D) an=an111a_n = a_{n-1} - 11
  1. Sequence Type Determination: We have the sequence: 1,12,23,34,45,56,1, 12, 23, 34, 45, 56, \ldots\newlineTo determine the type of sequence, we need to check the difference between consecutive terms.
  2. Calculate First Two Terms: Calculate the difference between the first two terms: 121=1112 - 1 = 11.
  3. Calculate Second and Third Terms: Calculate the difference between the second and third terms: 2312=1123 - 12 = 11.
  4. Conclusion of Sequence Type: Since the difference between consecutive terms is constant, we can conclude that the sequence is an arithmetic sequence with a common difference of 1111.
  5. Arithmetic Sequence Recursive Formula: The recursive formula for an arithmetic sequence is given by an=an1+da_n = a_{n-1} + d, where dd is the common difference.
  6. Substitute Common Difference: Substitute the common difference 1111 into the recursive formula to get the specific formula for this sequence: an=a(n1)+11a_n = a_{(n-1)} + 11.
  7. Comparison with Choices: Comparing the derived formula with the given choices, we find that the correct choice is (A)an=a(n1)+11(A)a_n = a_{(n-1)} + 11.

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