Which recursive formula can be used to define this sequence for n > 1? 9, 13, 17, 21, 25, 29, ... Choices: (A)a = 4a (B)a = 13/9a (C)a = a + a - 4 (D)a = a + 4

Sequence Type: We have the sequence: 9, 13, 17, 21, 25, 29, ... Is the given sequence geometric or arithmetic? The difference between consecutive terms is the same. The given sequence is arithmetic.Find Common Difference: Find the common difference, d. Two consecutive terms are 9 and 13. 13 - 9 = 4 Common difference (d): 4Recursive Formula: Identify the recursive formula for the given sequence. Since the sequence is arithmetic with a common difference of 4, the recursive formula will add this common difference to the previous term. Recursive formula: a_n = a_(n-1) + 4

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Which recursive formula can be used to define this sequence for n > 1? $\newline$ $9, 13, 17, 21, 25, 29, \ldots$ $\newline$ Choices: $\newline$ (A) $a_n = 4a_{n-1}$ $\newline$ (B) $a_n = \frac{13}{9}a_{n-1}$ $\newline$ (C) $a_n = a_{n-1} + a_{n-2} - 4$ $\newline$ (D) $a_n = a_{n-1} + 4$

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Math Problems

Algebra 1

Write a formula for a recursive sequence

Full solution

Q. Which recursive formula can be used to define this sequence for

n > 1

\newline

9, 13, 17, 21, 25, 29, \ldots

\newline

Choices:

\newline

(A)

a_n = 4a_{n-1}

\newline

(B)

a_n = \frac{13}{9}a_{n-1}

\newline

(C)

a_n = a_{n-1} + a_{n-2} - 4

\newline

(D)

a_n = a_{n-1} + 4

Sequence Type: We have the sequence: $9, 13, 17, 21, 25, 29, \ldots$ $\newline$ Is the given sequence geometric or arithmetic? $\newline$ The difference between consecutive terms is the same. $\newline$ The given sequence is arithmetic.
Find Common Difference: Find the common difference, $d$ . $\newline$ Two consecutive terms are $9$ and $13$ . $\newline$ $13 - 9 = 4$ $\newline$ Common difference ( $d$ ): $4$
Recursive Formula: Identify the recursive formula for the given sequence. $\newline$ Since the sequence is arithmetic with a common difference of $4$ , the recursive formula will add this common difference to the previous term. $\newline$ Recursive formula: $a_n = a_{n-1} + 4$