Which recursive formula can be used to define this sequence for n 1? 11, 23, 35, 47, 59, 71, ... Choices: (A)a = a + 12 (B)a = a - 12 (C)a = 23/11a (D)a = 12a

Question

Which recursive formula can be used to define this sequence for n > 1?   11, 23, 35, 47, 59, 71, ...    Choices: (A)a = a + 12 (B)a = a - 12 (C)a = 23/11a (D)a = 12a

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Sequence Type: We have the sequence: 11, 23, 35, 47, 59, 71, ... Is the given sequence geometric or arithmetic? The difference between consecutive terms is the same. The given sequence is arithmetic.Common Difference: Find the common difference, d. Two consecutive terms are 11 and 23. 23 - 11 = 12 Common difference (d): 12Recursive Formula: Identify the recursive formula for the given sequence. Since the common difference is 12, the recursive formula will add 12 to the previous term. Recursive formula: a_n = a_(n-1) + 12Matching Choices: Match the recursive formula with the given choices. The correct choice that represents the recursive formula a_n = a_(n-1) + 12 is: (A) a = a + 12 This is incorrect because it lacks the subscript n to denote the sequence term. (B) a = a - 12 This is incorrect because it subtracts 12 instead of adding it. (C) a = 23/11a This is incorrect because it implies a geometric sequence with a ratio of 23/11. (D) a = 12a This is incorrect because it implies multiplying the previous term by 12, which is not the case.  The correct recursive formula is not explicitly listed in the choices, but the intended correct choice seems to be (A) with a typographical error. It should be written as (A) a_n = a_(n-1) + 12.

Which recursive formula can be used to define this sequence for n > 1? $\newline$ $11, 23, 35, 47, 59, 71, \ldots$ $\newline$ Choices: $\newline$ (A) $a_{n} = a_{n-1} + 12$ $\newline$ (B) $a_{n} = a_{n-1} - 12$ $\newline$ (C) $a_{n} = \frac{23}{11}a_{n-1}$ $\newline$ (D) $a_{n} = 12a_{n-1}$

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