Q. Which of the following is not equivalent to cos5π ?cos511πcos(−59π)cos514πcos59π
Properties of Cosine Function: Understand the properties of the cosine function. The cosine function has a period of 2π, which means that cos(θ)=cos(θ+2πk) for any integer k. Also, cosine is an even function, so cos(θ)=cos(−θ).
Evaluate cos(511π): Evaluate cos(511π). Using the periodic property of cosine, we can subtract 2π (which is the same as 510π) from 511π to find an equivalent angle within the first period. cos(511π)=cos(511π−510π)=cos(51π) Since 51π is equivalent to 5π, this expression is equivalent to cos(5π).
Evaluate cos(−59π): Evaluate cos(−59π). Using the even property of cosine, we know that cos(θ)=cos(−θ). cos(−59π)=cos(59π) Now, we can add 2π (which is the same as 510π) to 59π to find an equivalent angle within the first period. cos(59π)=cos(59π+510π)=cos(519π) We can subtract 2π again to find an equivalent angle. cos(519π)=cos(519π−510π)=cos(59π) Since we have already established that cos(−59π)=cos(59π), this expression is equivalent to cos(−59π)1.
Evaluate cos(514π): Evaluate cos(514π). Using the periodic property of cosine, we can subtract 2π (which is the same as 510π) from 514π to find an equivalent angle within the first period. cos(514π)=cos(514π−510π)=cos(54π) Since 54π is not equivalent to 5π, this expression is not equivalent to cos(5π).
Evaluate cos(59π): Evaluate cos(59π). Using the periodic property of cosine, we can subtract 2π (which is the same as 510π) from 59π to find an equivalent angle within the first period. cos(59π)=cos(59π−510π)=cos(−51π) Using the even property of cosine, we know that cos(θ)=cos(−θ). cos(−51π)=cos(51π) Since 51π is equivalent to 5π, this expression is equivalent to cos(59π)0.
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