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Which of the following equations represents a line that passes through the points 
(-4,-6) and 
(2,0) ?
I. 
y+6=(x+9)
II. 
5x-5y=15
Neither
I only
II only
I and II

Which of the following equations represents a line that passes through the points (4,6) (-4,-6) and (2,0) (2,0) ?\newlineI. y+6=(x+9) y+6=(x+9) \newlineII. 5x5y=15 5 x-5 y=15 \newlineNeither\newlineI only\newlineII only\newlineI and II

Full solution

Q. Which of the following equations represents a line that passes through the points (4,6) (-4,-6) and (2,0) (2,0) ?\newlineI. y+6=(x+9) y+6=(x+9) \newlineII. 5x5y=15 5 x-5 y=15 \newlineNeither\newlineI only\newlineII only\newlineI and II
  1. Calculate Slope: Find the slope of the line passing through the points (4,6)(-4,-6) and (2,0)(2,0). The slope mm is calculated using the formula m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}. m=0(6)2(4)m = \frac{0 - (-6)}{2 - (-4)} m=66m = \frac{6}{6} m=1m = 1
  2. Write Point-Slope Equation: Use the slope and one of the points to write the equation of the line in point-slope form.\newlineWe can use the point (2,0)(2,0) and the slope m=1m = 1.\newlineThe point-slope form is yy1=m(xx1)y - y_1 = m(x - x_1).\newliney0=1(x2)y - 0 = 1(x - 2)\newliney=x2y = x - 2
  3. Check Equation I: Check if equation I, y+6=(x+9)y + 6 = (x + 9), represents the line with the slope found in Step 11.\newlineRewrite equation I in slope-intercept form (y=mx+by = mx + b).\newliney=x9+6y = -x - 9 + 6\newliney=x3y = -x - 3\newlineThe slope of this line is 1-1, which is not equal to the slope we found in Step 11 (m=1m = 1).\newlineTherefore, equation I does not represent the line passing through the points (4,6)(-4,-6) and (2,0)(2,0).
  4. Check Equation II: Check if equation II, 5x5y=155x - 5y = 15, represents the line with the slope found in Step 11.\newlineRewrite equation II in slope-intercept form (y=mx+by = mx + b).\newline5y=5x155y = 5x - 15\newliney=x3y = x - 3\newlineThe slope of this line is 11, which is equal to the slope we found in Step 11 (m=1m = 1).\newlineNow, we need to check if the line passes through one of the given points.
  5. Verify Point in Equation II: Substitute the point (2,0)(2,0) into equation II to verify if it satisfies the equation.\newliney=x3y = x - 3\newline0=230 = 2 - 3\newline0=10 = -1\newlineThis is not true, so the point (2,0)(2,0) does not lie on the line represented by equation II.\newlineTherefore, equation II also does not represent the line passing through the points (4,6)(-4,-6) and (2,0)(2,0).

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