Which of the following equations represents a line that passes through the points (6,2) and (-6,-14) ? I. y-1=(4)/(3)(x-6) II. 4x-3y=21 Neither I only II only I and II

Calculate slope: Calculate the slope of the line passing through the points (6,2) and (-6,-14). The slope (m) is given by the formula m = (y2 - y1) / (x2 - x1). Here, (x1, y1) = (6, 2) and (x2, y2) = (-6, -14). m = (-14 - 2) / (-6 - 6) m = (-16) / (-12) m = 4/3Check equation slope: Check if equation I, y - 1 = (4/3)(x - 6), has the correct slope. The slope-intercept form of a line is y = mx + b. In equation I, the slope is (4/3), which matches the slope we calculated in Step 1.Verify equation point: Verify if equation I passes through the point (6,2). Substitute x = 6 and y = 2 into the equation y - 1 = (4/3)(x - 6). 2 - 1 = (4/3)(6 - 6) 1 = (4/3)(0) 1 = 0 This is incorrect; therefore, equation I does not pass through the point (6,2).

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Which of the following equations represents a line that passes through the points
(6,2) and
(-6,-14) ?
I.
y-1=(4)/(3)(x-6)
II.
4x-3y=21
Neither
I only
II only
I and II

Which of the following equations represents a line that passes through the points $(6,2)$ and $(-6,-14)$ ? $\newline$ I. $y-1=\frac{4}{3}(x-6)$ $\newline$ II. $4 x-3 y=21$ $\newline$ Neither $\newline$ I only $\newline$ II only $\newline$ I and II

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Math Problems

Algebra 2

Write a quadratic function from its x-intercepts and another point

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Q. Which of the following equations represents a line that passes through the points

(6,2)

and

(-6,-14)

\newline

y-1=\frac{4}{3}(x-6)

\newline

II.

4 x-3 y=21

\newline

Neither

\newline

I only

\newline

II only

\newline

I and II

Calculate slope: Calculate the slope of the line passing through the points $(6,2)$ and $(-6,-14)$ . The slope $m$ is given by the formula $m = \frac{y_2 - y_1}{x_2 - x_1}$ . Here, $(x_1, y_1) = (6, 2)$ and $(x_2, y_2) = (-6, -14)$ . $m = \frac{-14 - 2}{-6 - 6}$ $m = \frac{-16}{-12}$ $m = \frac{4}{3}$
Check equation slope: Check if equation I, $y - 1 = \frac{4}{3}(x - 6)$ , has the correct slope. $\newline$ The slope-intercept form of a line is $y = mx + b$ . $\newline$ In equation I, the slope is $\frac{4}{3}$ , which matches the slope we calculated in Step $1$ .
Verify equation point: Verify if equation I passes through the point $(6,2)$ . $\newline$ Substitute $x = 6$ and $y = 2$ into the equation $y - 1 = \frac{4}{3}(x - 6)$ . $\newline$ $2 - 1 = \frac{4}{3}(6 - 6)$ $\newline$ $1 = \frac{4}{3}(0)$ $\newline$ $1 = 0$ $\newline$ This is incorrect; therefore, equation I does not pass through the point $(6,2)$ .