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Let’s check out your problem:
Which expression is equivalent to the expression below?
\newline
2
(
6
n
+
1
)
−
6
n
2(6 n+1)-6 n
2
(
6
n
+
1
)
−
6
n
\newline
6
n
+
2
6 n+2
6
n
+
2
\newline
2
(
6
n
+
1
−
6
n
)
2(6 n+1-6 n)
2
(
6
n
+
1
−
6
n
)
\newline
18
n
+
1
18 n+1
18
n
+
1
\newline
14
n
+
3
14 n+3
14
n
+
3
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Math Problems
Algebra 1
Simplify variable expressions involving like terms and the distributive property
Full solution
Q.
Which expression is equivalent to the expression below?
\newline
2
(
6
n
+
1
)
−
6
n
2(6 n+1)-6 n
2
(
6
n
+
1
)
−
6
n
\newline
6
n
+
2
6 n+2
6
n
+
2
\newline
2
(
6
n
+
1
−
6
n
)
2(6 n+1-6 n)
2
(
6
n
+
1
−
6
n
)
\newline
18
n
+
1
18 n+1
18
n
+
1
\newline
14
n
+
3
14 n+3
14
n
+
3
Distribute
2
2
2
into parentheses:
Distribute the
2
2
2
into the parentheses in the expression
2
(
6
n
+
1
)
2(6n+1)
2
(
6
n
+
1
)
.
2
(
6
n
+
1
)
=
2
⋅
6
n
+
2
⋅
1
=
12
n
+
2
2(6n+1) = 2\cdot6n + 2\cdot1 = 12n + 2
2
(
6
n
+
1
)
=
2
⋅
6
n
+
2
⋅
1
=
12
n
+
2
Subtract
6
n
6n
6
n
:
Subtract
6
n
6n
6
n
from the result of the distribution.
\newline
(
12
n
+
2
)
−
6
n
(12n + 2) - 6n
(
12
n
+
2
)
−
6
n
\newline
=
12
n
−
6
n
+
2
= 12n - 6n + 2
=
12
n
−
6
n
+
2
\newline
=
6
n
+
2
= 6n + 2
=
6
n
+
2
Compare with options:
Compare the result with the given options.
\newline
The expression
6
n
+
2
6n + 2
6
n
+
2
matches one of the given options.
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\newline
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\newline
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A
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10
(A)10
(
A
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10
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B
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\newline
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\newline
(A)
20
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