Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Which equation shows the distributive property of multiplication?\newlineChoices:\newline(A) cdf=gc \cdot d \cdot f = g\newline(B) c(df)=(cd)fc \cdot (d \cdot f) = (c \cdot d) \cdot f\newline(C) 0=c00 = c \cdot 0\newline(D) cdcf=c(df)c \cdot d - c \cdot f = c \cdot (d - f)

Full solution

Q. Which equation shows the distributive property of multiplication?\newlineChoices:\newline(A) cdf=gc \cdot d \cdot f = g\newline(B) c(df)=(cd)fc \cdot (d \cdot f) = (c \cdot d) \cdot f\newline(C) 0=c00 = c \cdot 0\newline(D) cdcf=c(df)c \cdot d - c \cdot f = c \cdot (d - f)
  1. Identify Property: Identify the distributive property of multiplication. The distributive property of multiplication over addition or subtraction is expressed as a×(b+c)=a×b+a×ca \times (b + c) = a \times b + a \times c or a×(bc)=a×ba×ca \times (b - c) = a \times b - a \times c. This property allows us to multiply a single term by each term inside a set of parentheses.
  2. Analyze Choice (A): Analyze each choice to see which one represents the distributive property.\newline(A) cdf=gc \cdot d \cdot f = g does not show the distributive property because there is no addition or subtraction within the parentheses that is being distributed.
  3. Analyze Choice (B): Analyze choice (B).\newline(B) c(df)=(cd)fc \cdot (d \cdot f) = (c \cdot d) \cdot f does not show the distributive property because it is an example of the associative property of multiplication, where the grouping of the factors does not affect the product.
  4. Analyze Choice (C): Analyze choice (C).\newline(C) 0=c00 = c \cdot 0 does not show the distributive property because it is an example of the multiplication property of zero, which states that any number multiplied by 00 is 00.
  5. Analyze Choice (D): Analyze choice (D).\newline(D) cdcf=c(df)c \cdot d - c \cdot f = c \cdot (d - f) does show the distributive property because it demonstrates that multiplying cc by the difference of dd and ff is the same as multiplying cc by dd and then subtracting the product of cc and ff.

More problems from Properties of multiplication