Which equation shows the commutative property of multiplication? Choices: (A)0 = 0 · g (B)j + k = g · h (C)h · g = g · h (D)g · h − g · j = g · (h − j)

Identify Property: Identify the property of multiplication that involves rearranging the factors without changing the product. Review Choices: Review each choice to see which one demonstrates the commutative property, which states that a * b = b * a. Check (A): Check choice (A): 0 = 0 · g. This is an identity property example, not commutative. Check (B): Check choice (B): j + k = g · h. This involves addition and multiplication, not purely demonstrating commutative property. Check (C): Check choice (C): h · g = g · h. This matches the definition of the commutative property, where the order of multiplication does not affect the outcome. Check (D): Check choice (D): g · h − g · j = g · (h − j). This is an example of the distributive property, not commutative.

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Which equation shows the commutative property of multiplication? $\newline$ Choices: $\newline$ (A) $0 = 0 \cdot g$ $\newline$ (B) $j + k = g \cdot h$ $\newline$ (C) $h \cdot g = g \cdot h$ $\newline$ (D) $g \cdot h - g \cdot j = g \cdot (h - j)$

View step-by-step help

Home

Math Problems

Algebra 1

Properties of addition and multiplication

Full solution

Q. Which equation shows the commutative property of multiplication?

\newline

Choices:

\newline

(A)

0 = 0 \cdot g

\newline

(B)

j + k = g \cdot h

\newline

(C)

h \cdot g = g \cdot h

\newline

(D)

g \cdot h - g \cdot j = g \cdot (h - j)

Identify Property: Identify the property of multiplication that involves rearranging the factors without changing the product.
Review Choices: Review each choice to see which one demonstrates the commutative property, which states that $a \times b = b \times a$ .
Check (A): Check choice (A): $0 = 0 \cdot g$ . This is an identity property example, not commutative.
Check (B): Check choice (B): $j + k = g \cdot h$ . This involves addition and multiplication, not purely demonstrating commutative property.
Check (C): Check choice (C): $h \cdot g = g \cdot h$ . This matches the definition of the commutative property, where the order of multiplication does not affect the outcome.
Check (D): Check choice (D): $g \cdot h - g \cdot j = g \cdot (h - j)$ . This is an example of the distributive property, not commutative.